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Yuliya22 [10]
3 years ago
7

Can someone please answer. There is one problem. There's a picture. Thank you!

Mathematics
2 answers:
cupoosta [38]3 years ago
8 0
1 cheese from 3 cheeses

3 toppings from 8 toppings.

Number of ways:     Note the order is irrelevant.

=  ³C₁ * ⁸C₃

=  3/1  *    8*7*6/(3*2*1) =  3 * 56 =      168
laila [671]3 years ago
3 0
The answer is D, or 168. 
The cheese can be any one out of 3 = 3 choices.  For each of those . . .
The first topping can be any one of 8.  For each of those . . .
The second topping can be any one of the remaining 7 . For each of those . . .
The third topping can be any one of the remaining 6 .

Total number of ways to assemble a pizza = (3 x 8 x 7 x 6) =  1,008 ways.

<span>BUT . . . </span>

You could choose the SAME 3 toppings in (3 x 2) = 6 different ways, and
nobody could tell the difference once they were selected.  All 6 different
ways would result in the same pizza.

So, out of the 1,008 total different ways there are of choosing ingredients,
<span>there are only ( 1,008 / 6 ) = </span>168<span> different and distinct pizzas.</span>
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