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STALIN [3.7K]
3 years ago
9

-3x-8y=20 -5x+y=19 substitute

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
4 0
-3x-8y=20\\ \\ -5x+y=19

First let's multiply the first equation by -5 and the second one by 3

-5\cdot (-3x-8y)=-5\cdot 20\\ \\ 15x+40y=-100

3\cdot (-5x+y)=3\cdot 19\\ \\ -15x+3y=57\\

And now let's add these two new equations.


15x+40y=-100\\ \\ -15x+3y=57\\ \\ (15x+40y)+(-15x+3y)=-100+57\\ \\ 15x-15x+40y+3y=-43\\ \\ 43y=-43\\ \\ y=\quad \frac { 43 }{ -43 } \\ \\ y=\quad -1

We found y's value. Let's put it in one of the equations to find x.

y=\quad -1\\ \\ -3x-8y=20\\ \\ -3x-8\cdot -1=20\\ \\ -3x+8=20\\ \\ -3x=20-8\\ \\ -3x=12\\ \\ x=\quad \frac { 12 }{ -3 } \\ \\ x=-4

<span>Solution : (-4, -1)

Good Luck !

</span><span>
</span>
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Answer:

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