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2 years ago

Pls help solve part c

Mathematics

1 answer:

Tresset [83]2 years ago

8 0

Answer:

See image below

Step-by-step explanation:

Every point starting at the y axis and extending left to ∞ represents the inequality x ≤ 0

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For any nonnegative real number.

frutty [35]

Answer:

Step-by-step explanation:

We know that $\sqrt{b}=b^{1/2}$ .

We also know that $(a^b)^c=a^{bc}$ .

We can combine these facts to get $(\sqrt{b})^2=(b^{1/2})^2=b^{1/2*2}=b^{1}=b$ .

So, the answer is $\boxed{A}$ and we're done!

<em>Note: the non-negative part or the equation comes from the fact that you assume the square root of a negative number doesn't exist. You will change this assumption later in the year, or in further years.</em>

5 0

3 years ago

A scalene triangle has an angle that measures 47∘ and a second angle that measures 88∘. What is the measure of the third angle?

umka21 [38]

Answer:

45°

Step-by-step explanation:

The angles of any triangle add up to 180 degrees

add the two known angles: 47+88=135

then subtract the sum from 180 to get answer: 180-135=45

5 0

4 years ago

Read 2 more answers

Pls help with this maths question... feels like I'm missing something easy ;/

Wewaii [24]

Answer:

10.34 cm.

Step-by-step explanation:

First we need to calculate the angle between the hour and minute hand

We see that there are 5 * 5-minute intervals between the 2 hands and the clock has 12 * 5-minute intervals, so:

This is 5/12 * 360 = 150 degrees,

So we apply the Cosine Rule to the triangle:

x^2 = 4.5^2 + 6.2^2 - 2*4.5*6.2cos150

= 107.014

x = √107.14 = 10.34.

7 0

3 years ago

Read 2 more answers

In a random sample of 180, what is the probability that more than 50 have completed four years of colllege?

Naddik [55]

0.0816 is the probability so around only 3% so around only 5 or 6 people out of the total 180.

3 0

4 years ago

Es LOGICA PROPOSICIONAL, me pueden ayudar porfavor?

madreJ [45]

$\begin{array}{c|c|c|c} p & q & \neg q & p \land \neg q \\ T & T & F & F \\ T & F & T & T \\ F & T & F & F \\ F & F & T & F \end{array}$

$\begin{array}{c|c|c|c} t & s & \neg t & \neg t \implies s \\ T & T & F & T \\ T & F & F & T \\ F & T & T & T \\ F & F & T & F \end{array}$

$\begin{array}{c|c|c}p\land \neg q & \neg t \implies s & (p \land \neg q) \implies (\neg t \implies s) \\T & T & T \\ T & F & F \\ F & T & T \\ F & F & T \end{array}$

The given logical statement is false when $p\land\neg q$ and $\neg t\implies s$ are true and false, respectively.

$p\land\neq g$ is true when $p$ is true and $q$ is false
$\neg t \implies s$ is false when both $t$ and $s$ are false

6 0

2 years ago