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3 years ago

Pls help with this maths question... feels like I'm missing something easy ;/

Mathematics

2 answers:

Wewaii [24]3 years ago

7 0

Answer:

10.34 cm.

Step-by-step explanation:

First we need to calculate the angle between the hour and minute hand

We see that there are 5 * 5-minute intervals between the 2 hands and the clock has 12 * 5-minute intervals, so:

This is 5/12 * 360 = 150 degrees,

So we apply the Cosine Rule to the triangle:

x^2 = 4.5^2 + 6.2^2 - 2*4.5*6.2cos150

= 107.014

x = √107.14 = 10.34.

Jobisdone [24]3 years ago

4 0

Missing length is 10.3cm to 1.d.p

The clock is a circle divided into 12

360/12=30 degrees for each part

1) 7 to 8

2) 8 to 9

3) 9 to 10

4) 10 to 11

5) 11 to 12

5 parts

30 x 5 = 150 degrees

We've got an angle between 2 lengths - cosine rule comes to mind for me.

a = root 6.2^2 + 4.5^2 - 2x6.2 4.5 x cos 150

= 10.34476764

length is 10.3cm to 1.d.p

(the others are to 1.d.p too)

Hope this helps!

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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

Mashutka [201]

Here is the full question

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.

Equation:

y=-16x^2+153x+98

Answer:

10.2 seconds

Step-by-step explanation:

Given equation :

$y=-16x^2+153x+98$ shown the expression of a quadratic equation

Let y =0

∴

0 = $-16x^2+153x+98$

where;

$a=-16\\b=153\\c=98$

Using the quadratic formula:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

replacing it with our values; we have:

$x=\frac{-153\±\sqrt{153^2-4(-16)(98)}}{2(-16)}$

$x=\frac{-153\ + \sqrt{153^2-4(-16)(98)}}{2(-16)}$ OR $x=\frac{-153\ - \sqrt{153^2-4(-16)(98)}}{2(-16)}$

$x_1=10.17$ OR $x_2=-0.60$

Hence, we go by the positive value since, is the time that the rocket will hit the ground.

x= 10.17

x = ≅ 10.2 seconds

Therefore, the rocket will hit the ground, to the nearest 100th of second. = 10.2 seconds

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4 years ago

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saw5 [17]

Answer:

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Step-by-step explanation:

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3 years ago

Sonbull [250]

Answer:

$x=\boxed{6.6}$

$\overline{\sf DE}=\boxed{13.2}\:\:\sf units$

Step-by-step explanation:

Geometric Mean Theorem - Altitude Rule

The altitude drawn from the vertex of the right angle perpendicular to the hypotenuse separates the hypotenuse into two segments. The ratio of one segment to the altitude is equal to the ratio of the altitude to the other segment:

$\sf \dfrac{segment\:1}{altitude}=\dfrac{altitude}{segment\:2}$

From inspection of the given diagram:

altitude = FD = 9
segment 1 = CD = 5
segment 2 = DE = $2x+3$

$\begin{aligned}\sf \dfrac{segment\:1}{altitude} & = \sf \dfrac{altitude}{segment\:2}\\\\\implies \dfrac{5}{9} & = \dfrac{9}{2x+3}\\\\5(2x+3) & = 81\\\\10x+15 & = 81\\\\10x & = 66\\\\ \implies x & = 6.6\end{aligned}$

Substitute the found value of x into the expression for DE:

$\begin{aligned}\sf \overline{DE} & = 2x+3\\\implies \sf \overline{DE} & = 2(6.6)+3\\& = 13.2+3\\& =16.2\:\: \sf units\end{aligned}$

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2 years ago

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3 years ago

4y = 42 - 3y Can you help me find y?

Lesechka [4]

4y = 42 - 3y

First, add '3y' to both of the sides.
$4y + 3y = 42$
Second, add '4y + 3y' to get '7y'.
$7y = 42$
Third, divide both sides by '7'.
$y = \frac{42}{7}$
Fourth, how many times does 7 go into 42? 42 ÷ 7 = '6'.
$y = 6$

Answer: y = 6

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3 years ago

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Pls help with this maths question... feels like I'm missing something easy ;/​

Pls help with this maths question... feels like I'm missing something easy ;/