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luda_lava [24]
1 year ago
14

Write the following using index notation:

Mathematics
2 answers:
blagie [28]1 year ago
6 0

Step-by-step explanation:

4^2

5^4

3^1×7^4

2^2 ×9^4

Ainat [17]1 year ago
3 0
A. 4^2
b. 5^4
c. 3 x 7^4
d. 2^2 x 9^4
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2. Not Parallelogram

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The following information is given for Tripp Company, which uses the indirect<br> method
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Answer:

Step-by-step explanation:

1.

The cash flow from operating activities is = $28000.

Working Note:

Net Income                                                        $20000

Depreciation expense                                   $3000

Increase in accounts receivable                 ($2000)

Increase in accounts payable                      $4000

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Net Cash Flow from Operating Activities = 20000 + 3000 – 2000 + 4000 + 3000

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2.

The cash flow from investing activities = $6000.

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Net cash flow from investing activities =               $6000

3.

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7 0
3 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
2 years ago
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