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2 years ago

Write the following using index notation:

Mathematics

2 answers:

blagie [28]2 years ago

6 0

Step-by-step explanation:

4^2

5^4

3^1×7^4

2^2 ×9^4

Ainat [17]2 years ago

3 0

A. 4^2
b. 5^4
c. 3 x 7^4
d. 2^2 x 9^4

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Find the equation of the line that passes through the points (6,14) and is parallel to y=-4/3x-1

Yuri [45]

Answer:

y= -4/3 + 22

Step-by-step explanation:

y= -4/3x -1

14 = -4/3 (6) + b

14= -8 + b

22= b

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3 years ago

Factor 3/4 out of 3/4z + 6

Alenkasestr [34]

ANSWER

$\frac{3}{4} z + 6 = \frac{3}{4} (z + 8 )$

EXPLANATION

We want to factor
$\frac{3}{4}$
out of

$\frac{3}{4} z + 6$

The first term is already having a factor of
$\frac{3}{4}$
The constant term which is the second term is not having a factor of
$\frac{3}{4}$
so we need to use a trick of multiplying and dividing by the same factor to obtain,

$\frac{3}{4} z + 6 = \frac{3}{4} z + \frac{3}{4} \times \frac{6}{ \frac{3}{4} }$

We can now factor
$\frac{3}{4}$
out of the right hand side to obtain,

$\frac{3}{4} z + 6 = \frac{3}{4} (z + \frac{6}{ \frac{3}{4} } )$
Let us rewrite the right most fraction using the normal division symbol.

$\frac{3}{4} z + 6 = \frac{3}{4} (z + 6 \div \frac{3}{4} )$

We simplify to obtain,

$\frac{3}{4} z + 6 = \frac{3}{4} (z + 6 \times \frac{4}{3} )$

This further gives us,

$\frac{3}{4} z + 6 = \frac{3}{4} (z + 2 \times 4 )$

$\frac{3}{4} z + 6 = \frac{3}{4} (z + 8 )$

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3 years ago

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If the first of three consecutive integers is subtracted from 138, the result is the sum of the second and third. What are the i

Murljashka [212]

Answer:

Step-by-step explanation:

n, n + 1, n + 2 - three consecutive integers

The equation:

138 - n = (n + 1) + (n + 2)

138 - n = n + 1 + n + 2 combile like terms

138 - n = 2n + 3 subtract 138 from both sides

-n = 2n - 135 subtract 2n from both sides

-3n = -135 divide both sides by (-3)

n = 45

n + 1 = 46

n + 2 = 47

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3 years ago

What is the area of this figure. 128 in 136 in 153 in 258 in

aliya0001 [1]

So, to find the solution to this problem, we will we using pretty much the same method we used in your previous question. First, let's find the area of the rectangle. The area of a rectangle is length x width. The length in this problem is 16 and the width is 3, and after multiplying these together, we have found 48 in^2 to be the area of the square. Next, we can find the area of the trapezoid. The area of a trapezoid is ((a+b)/2)h where a is the first base, b is the second base, and h is the height. In this problem, a=16, b=5, and h=10. So, all we have to do is plug these values into the area formula. ((16+5)/2)10 = (21/2)10 = 105. So, the area of the trapezoid is 105 in^2. Now after adding the two areas together (48in^2 and 105in^2), we have found the solution to be 153in^2. I hope this helped! :)

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3 years ago

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olga55 [171]

The answer is C to the question

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3 years ago

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