<span>13-((4/5)+(6/8))
Make your fractions have common denominators
</span>13-((32/40)+(30/40))
Add your fractions and simplify
13-(62/40)
or
13-(31/20)
or
13-(1 11/20)
Then turn 13 into a fraction with a common denominator! Im going to use the second fraction method (31/20)
13 written as a fraction is 13/1, its LCD with 31/20 is 20. I now multiply the top and bottom by 20
260/20
Now I rewrite the problem again
(260/20)-(31/20)
Which equals
229/20!
This is your unsimplified answer
Finally you simplify and get
11 9/20
Answer:
288
Step-by-step explanation:
<em> Number of rectangles</em>
<em>____________________________________________________________</em>
1 × 1 squares 9-1 = 1 = 8*8 = 64
1 × 2 squares 9-2 = 7 = 8*7 = 56
1 × 3 squares 9-3 = 6 = 8*6 = 48
1 × 4 squares 9-4 = 5 = 8*5 = 40
1 × 5 squares 9-5 = 4 = 8*4 =32
1 × 6 squares 9-6 = 3 = 8*3 = 24
1 × 7 squares 9-7 = 2 = 8*2 = 16
1 × 8 squares 9-8 = 1 = 8*1 = 8
64 + 56 + 48 + 40 + 32 + 24 + 16 + 8 = 288
<em>Thus,</em>
<em>the number of squares on a chessboard is 228.</em>
<em />
<em>Hope this helps :)</em>
The share of Natasha is £ 42
<em><u>Solution:</u></em>
£70 is divided between Natasha, Richard & Stephen
Total amount = 70
Let the share of natasha be "x"
Let the share of richard be "y"
Let the share of stephen be "z"
Natasha gets twice as much as Richard
x = 2y ------ eqn 1
Richard gets three times as much as Stephen
y = 3z
----- eqn 2
Total amount = 70
share of natasha + share of richard + share of stephen = 70
x + y + z = 70
Substitute eqn 1 and eqn 2
Substitute y = 21 in eqn 1
x = 2y = 2(21) = 42
x = 42
Thus natasha gets £ 42
Theoretical probability is based on the likelihood of events.
if a coin is flipped 20 times, and it has landed on heads 4 times, theres a 50% chance it would land on heads the 5th time.
it could be that heads gets more than tails or it could be vise versa.
The probability of getting two heads is 1 in 4.
