400 miles -----------4 hours
X miles ------------2 hours
4x=400.2
4x=800
X=200
Or
400miles --------------- 4hours
X miles --------------- 6 hours
4x=400.6
4x=2.400
X= 600
About 38 cars. 300/8= 37.5 cars. There is no such thing as 0.5 of a car so round up to the nearest whole number.
Answer:
Height of shuttle at that instant = 1.17 miles
Step-by-step explanation:
Refer the given figure.
C is the position of rocket and B is the position of observer.
Here we need to find AC, that is the height of shuttle at that instant.
Using trigonometric rules on ΔABC, we have

Height of shuttle at that instant = AC = 1.17 miles