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patriot [66]
3 years ago
15

At the movie theater child admission is $5.90 and adult is $9.00. Wednesday 145 tickets were sold for a total sales of 1115.90.

How many adult tickets were sold that day? ​
Mathematics
1 answer:
Anettt [7]3 years ago
8 0

Answer:1160.3

1169.30-9.00

Step-by-step explanation:1169.30-9.00

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Qualitative data are made up of words rather than numbers. Because of this, analyzing the data is _____________. (Select all tha
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Answer: 6328723894

Step-by-step explanation:

4 0
2 years ago
Does this graph represent a function? What is the domain and range of the graph
Daniel [21]
Yes it is a function. It passes the vertical line test. In other words, it is impossible to draw a single vertical line through more than one point on the V shaped graph. Any input leads to exactly one output.

The domain is the set of all real numbers. This is because we can plug in any x value leading to some specific y value. There are no holes or gaps or jumps to indicate we must restrict any given x value. The domain would not be the set of whole numbers only because values between the whole numbers (eg: decimal values like x = 2.75) work just fine. 

The range is the set of y values such that y is either 0 or larger than 0. In short, the range is y \ge 0. Notice how any point on the V shaped graph has a y coordinate that is either 0 or larger than 0. It is impossible to get a y value that is negative.

--------------------------------------------------------------------

In summary,
Yes it is a function
Domain: all real numbers
Range: y \ge 0
So the answer is choice B
6 0
3 years ago
Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball
Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and 51\frac{1}{3} yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from 51\frac{1}{3} yards.

\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}

Let us have a common denominator.

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}  

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}

\text{1 yard}=3\text{ feet}

\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}

\frac{28}{3}\text{ yards}=28\text{ feet}

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

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3 years ago
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3 years ago
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