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1 year ago

D

1 answer:

7 0

The type of organizational learning that involves a formal approach to familiarize a new staff member with the organization's values and policies is <u>B. employee orientation</u>.

<h3>What is organizational learning?</h3>

Organizational learning involves the process of gaining experience and creating knowledge for organizational improvement.

Organizational learning enables employees to:

Share insights
Brainstorm together
Solve problems
Improve performance.

Thus, familiarizing new staff members with the organization's values and policies involves <u>employee orientation</u>, not employee mentorship, training, or development.

Learn more about employee orientation as part of organizational learning at brainly.com/question/11815347

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If the factory overhead is underapplied, then the adjusting journal entry to close the factory overhead account includes a: (Che

Ymorist [56]

Answer:

Debit to cost of goods sold and credit to factory overhead

Explanation:

Here we are interested in knowing the appropriate journal entry when the factory overhead is under applied.

What happens to the factory overhead journal in this case is that the we should have an adjusting journal entry.

The adjusting journal entry here is that we debit cost of goods sold and credit factory overhead

5 0

3 years ago

Accounts Payable: $19,207

lisabon 2012 [21]

Answer:

total liabilities = $169,008

Explanation:

total liabilities:

Accounts Payable: $19,207
Discount on Bonds Payable: ($7,000) ⇒ contra liability account
Sales Tax Payable: 3,512
FICA Tax Payable: 3,200
Bonds Payable: 100,000
Note Payable, due in two years 1,709
Unearned Service Revenue 30,500 ⇒ must be reported as a liability
Salaries and Wages Payable 17,880

to determine the total liabilities we just have to add both current and long term liabilities, and subtract any contra liability accounts = $176,008 - $7,000 = $169,008

7 0

2 years ago

A limited liability company that has two or more members can be taxed as a corporation.

Novosadov [1.4K]

It's true a limited liability company that has two or more members can be taxed as a corporation.

Option A) is true.

If you form a multiple-member LLC and do not file a special form with the IRS, the LLC will be taxed as if it were a partnership. You may elect to be treated as an S Corporation by filing IRS Form 2553, Election by a Small Business Corporation.

A multi-member limited liability company is treated as a pass-through entity for federal income tax purposes. As with a sole proprietorship GmbH, this means that the GmbH does not pay its own taxes. Instead, each member pays taxes on the company's income in proportion to their interest in the LLC.

Learn more about limited liability company at

brainly.com/question/13304738

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3 0

1 year ago

A university officer wants to know the proportion of registered students that spend more than 20 minutes to get to school. He se

vlada-n [284]

Answer:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

$n\hat p =25*0.52= 13 \geq 10$

$n(1-\hat p) = 25*(1-0.52) =12 \geq 10$

So then we satisfy this condition

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

$p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})$

So then the answer for this case would be:

a. Yes.

Explanation:

For this case we assume that the question is: If in the experiment described we can use the normal approximation for the proportion of interest.

For this case we have a sample of n =25

And we are interested in the proportion of registered students that spend more than 20 minutes to get to school.

X = 13 represent the number of students in the sample selected that have a time more than 20 min.

And then the estimated proportion of interest would be:

$\hat p = \frac{X}{n}= \frac{13}{25}= 0.52$

And we want to check if we can use the normal approximation given by:

$p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})$

So in order to do this approximation we need to satisfy some conditions listed below:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

$n\hat p =25*0.52= 13 \geq 10$

$n(1-\hat p) = 25*(1-0.52) =12 \geq 10$

So then we satisfy this condition:

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

$p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})$

So then the answer for this case would be:

a. Yes.

3 0

3 years ago

Ms. Liu shares her web data with you, which shows that she has an average of 500 daily page views during the weekdays, and an av

irakobra [83]

Answer:

1,250 on weekdays and 800 on weekends

Explanation:

During weekdays, each visitor views Ms. Liu's page twice, so the total number of visitors per day = 500 daily views / 2 views per visitor = 250 visitors per day. To calculate the total number of visitors for the five weekdays = 250 visitors per day x 5 days = 1,250 visitors

During weekends, each visitor views Ms. Liu's page three times, so the total number of visitors per weekend day = 1,200 daily views / 3 views per visitor = 400 visitors per day. To calculate the total number of visitors for the two weekend days = 400 visitors per day x 2 days = 800 visitors

6 0

3 years ago