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Tatiana [17]
2 years ago
7

Each of 36 students at a school play bought either a cup of orange juice or a sandwich. A cup of orange juice costs $1 and a san

dwich costs $3. The total amount collected was $76. How many students bought orange juice, and how many bought a sandwich?
Let represent the number of students who bought a cup of orange juice and represent the number of students who bought a sandwich. Then the problem can be represented by this system of equations:

+ 3 = 76
+ = 36

Answer the questions to solve the problem.

1. Explain what you should do with the two equations to eliminate one of the variables.
Mathematics
1 answer:
ELEN [110]2 years ago
5 0

In order to eliminate one of the variables, subtract one of the equation from the other equation.

<h3>How to eliminate one of the variables?</h3>

Given these equations:

o + 3s = 76 equation 1

o + s = 36 equation 2

Where:

o = number of orange juice bought

s = number of sandwiches bought

In order to eliminate one of the variables, subtract equation 2 from equation 1. The result is :

2s = 40

s = 20

To learn more about simultaneous equations, please check: brainly.com/question/25875552

#SPJ1

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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

[PS]   y - 11 = 3(x - 2)

<u>Step 2: Rewrite</u>

<em>Find Standard Form</em>

  1. Distribute 3:                                  y - 11 = 3x - 6
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  4. Factor -1:                                       -1(3x + y) = 5
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