Answer:
The nuclear utility environment is one of strict cost control under prescriptive regulations and increasing public scrutiny. This paper presents the results of A Total Quality approach, by a dedicated team, that addresses the need for increased on-site spent fuel storage in this environment. Innovations to spent fuel pool reracking, driven by utilities' specific technical needs and shrinking budgets, have resulted in both product improvements and lower prices. A Total Quality approach to the entire turnkey project is taken, thereby creating synergism and process efficiency in each of the major phases of the project: design and analysis, licensing, fabrication, installation and disposal. Specific technical advances and the proven quality of the team members minimizes risk to the utility and its shareholders and provides a complete, cost effective service. Proper evaluation of spent fuel storage methods and vendors requires a full understanding of currently available customer driven initiatives that reduce cost while improving quality. In all phases of a spent fuel reracking project, from new rack design and analysis through old rack disposal, the integration of diverse experts, at all levels and throughout all phases of a reracking project, better serves utility needs. This Total Quality environment in conjunction with many technical improvements results in a higher quality product at a lower cost
The prediction of minor actinides amounts accumulated in the spent fuel in China
International Nuclear Information System (INIS)
Zhou Peide
2000-01-01
The amounts of the Minor Actinides accumulated in the spent fuel are predicted according to the Nuclear Power Plant development plan envisaged in China. The Minor Actinides generated in the spent fuel unloaded from a typical PWR per year are calculated. The decay characteristics of the Minor Actinides during storage and cooling period are also calculated. At last, the Minor Actinides amounts accumulated in all spent fuel which were unloaded before sometime are given
Answer:
x^2y^4
Step-by-step explanation:
8 divided by 8 = 1
x divided by x^2 = x
y^3 divided by y = y^2
(xy^2)^2 = x^2y^4
Answer:
L(t) = 5·sin(πt) +7
Step-by-step explanation:
The middle of the oscillation of the given function occurs when t=0. At that point, ...
L(0) = d = 7
The next maximum of the oscillation occurs when the argument of the sine function is π/2.
b·t = π/2
b = π/(2t) = π/(2·0.5) = π
At that maximum, the length is 12, so we have ...
L(0.5) = a·sin(0.5π) +7 = 12
a = 5
The function L(t) is ...
L(t) = 5·sin(πt) +7
Answer:
hmmmm........
Step-by-step explanation:
radius is 4/2=2m
volume of the cylinder is equal
to πr^h
i.e, π(2m)^2×7m
≈88 m^3
