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Bond [772]
3 years ago
13

A pole vaulter uses a 15 foot long pole. she grips the pole so that the segment below her left hand is twice the length of the s

egment above her left hand. her right hand grips thee pole 1.5 feet above her left hand. how far up the pole is her right hand
Mathematics
1 answer:
ddd [48]3 years ago
5 0
Answer: The pole is 3.5 foot above the right hand.
To answer this question first you need to determine the left hand height/position. The left hand divides the pole segment into 2:1 ratio. If the pole if 15 foot long, then the equation will be:
2/(2+1)x 15 foot= 10 foot.

The left hand is located 10 foot from the ground and the right hand is 1.5 foot above it. Then the right hand position from the ground is:
10 foot+ 1.5 foot= 11.5 foot

Since the right hand is 11.5 foot from ground and the pole is 15 foot long, then the equation will be:
15 foot- 11.5 foot= 3.5 foot.
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