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2 years ago

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There are eight shirts in your closet, three blue, two are black, one is green, and two are white. You randomly select one to we

ar on Monday and then a different one on Tuesday. What is the probability that you wear blue shirts on both days?
(please write an explanation)

1 answer:

Maru [420]2 years ago

4 0

The probability of wearing blue shirts on both days is 3/28.

<h3>What is probability?</h3>

Probability is the measure of the likelihood of an occurrence.

Given:

8 shirts are available out of which 3 are blue, 1 is green and 2 are white.

P(blue on Monday) = 3/8

Now, 7 shirts are left to wear on Tuesday

P(blue on Tuesday) =2/7

So,

the probability of wearing blue shirts on both days = 3/8 * 2/7 = 3/28

Learn more about probability here:

brainly.com/question/24756209

#SPJ1

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A freshly inoculated bacterial culture of Streptococcus contains 100 cells. When the culture is checked 60 minutes later, it is

Luba_88 [7]

Answer:

$P(t) = 100e^{0.0251t}$

The doubling time is of 27.65 minutes.

Step-by-step explanation:

Exponential equation of growth:

The exponential equation for population growth is given by:

$P(t) = P(0)e^{kt}$

In which P(0) is the initial value and k is the growth rate.

A freshly inoculated bacterial culture of Streptococcus contains 100 cells.

This means that $P(0) = 100$ . So

$P(t) = 100e^{kt}$

When the culture is checked 60 minutes later, it is determined that there are 450 cells present.

This means that $P(60) = 450$ , and we use this to find k. So

$450 = 100e^{60k}$

$e^{60k} = 4.5$

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$60k = \ln{4.5}$

$k = \frac{\ln{4.5}}{60}$

$k = 0.0251$

So

$P(t) = 100e^{0.0251t}$

Doubling time:

This is t for which P(t) = 2P(0) = 200. So

$200 = 100e^{0.0251t}$

$e^{0.0251t} = 2$

$\ln{e^{0.0251t}} = \ln{2}$

$0.0251t = \ln{2}$

$t = \frac{\ln{2}}{0.0251}$

$t = 27.65$

The doubling time is of 27.65 minutes.

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3 years ago

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LenKa [72]

Answer:

y = $\frac{2}{3}$

Step-by-step explanation:

Given that y varies inversely with x then the equation relating them is

y = $\frac{k}{x}$ ← k is the constant of variation

To find k use the condition y = $\frac{1}{3}$ when x = $\frac{1}{2}$ , thus

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k = $\frac{1}{6}$

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When x = $\frac{1}{4}$ , then

y = $\frac{1}{6(\frac{1}{4}) }$ = $\frac{1}{\frac{3}{2} }$ = $\frac{2}{3}$

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q = 5√2

<span>Hope this answers the question. Have a nice day.</span>

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