Answer:
2nd - (w - 5)(w + 5)
4th - (-4v - 9)(-4v + 9)
Step-by-step explanation:
1. The first option shows an expression multiplied by its opposite(x -1), so therefore, it does not show the difference of squares
2. The second option does show the difference of squares because it is in the form (a + b)(a - b)
3. The third option is just a square because the same expression is multiplied by itself.
4. The fourth option is the difference of squares because it is in the form (a + b)(a - b). a equals -4v and b equals 9 in this case.
5. The fifth option is not the difference of squares. No term in common in both expressions
6. The sixth option is just a square because the same expression is multiplied by itself.
In all, there are two options that are the difference of squares, the 2nd and 4th.
Answer:
6 items are being purchased
Step-by-step explanation:
Given that variable p represents the number of items being purchased, and the variable t represents the time required to ring up the customer, If it takes 44 seconds to ring up a customer then the number of items being purchased may be computed by substituting the value of t into the given equation
t = 4p + 20.
Using t = 44
44 = 4p + 20
collect like terms or subtract 20 from both sides
44 - 20 = 4p
24 = 4p
Divide both sides by 4
24/4 = p
p = 6
As the ratio of your shadow to your height is 2:1 assuming the flagpole would form a similar triangle the shadow is twice the height of the pole meaning the pole is 14 feet tall
Answer:
£1443.89
Step-by-step explanation:
To start you take the £1700 and multiply it by 4% (or .04) to find how much it depreciates for the first year. For the first year the depreciation £68 so the next year it will be worth £1632 ( £1700 - 68). You do the same thing for the second year but you start with the amount its worth now (£1632) and multiply again by the 4%. The depreciation for the second year is 65.28. Now you take what it was worth at the start of the year (£1632) and subtract the depreciation for the second year (65.28) to get £1566.72. You do the same process again for the third year to end up with a value of £1504.05. Now for the 4th year you will take the value of £1504.05 and again multiply by the depreciation rate of 4% to find the last amount of depreciation which is £60.16. Take your starting value for year 4 (£1504.05) and subtract the amount of depreciation (£60.16) to get your answer of £1443.89.
Answer:
a) True
b) False
c) False
d) False
e) True
Step-by-step explanation:
a) Each basis of V has four vectors. Then any set of 5 vectors must be linear dependent (LD).
b) Suppose that 
is a basis of V. Considere the set 
where 
are scalars. The set has 5 vectors but 
because 
is not belong to A and is linear independent of 
c) Suppose that is a basis of V. Considere the set 
where 
are scalars. A has four nonzero vectors but isn't a basis because is a LD set.
d) Suppose that is a basis of V. Considere the set 
where are scalars. A has 3 nonzero vectors but isn't a basis because is a LD set.
e) Since any basis of V must have 4 elements, then a set of three vectors cannot generate V.
