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2 years ago

0.416 rounded to the nearest thousandth place

Mathematics

1 answer:

IgorC [24]2 years ago

6 0

It's gonna be 0.416 because 6 is in the thousandths place and nothing it next to it

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On a map, Sanford, NC and Myrtle Beach, SC are 4 inches apart. The distance between cities is actually 156 miles. What scale was

defon

Answer:

39 or 1/39

Step-by-step explanation:

You need to divide these but it depends on how you divide them

4/156=1/39
156/4=39

8 0

3 years ago

Here's another math question for y'all

lapo4ka [179]

Answer:65

Step-by-step explanation:

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2 years ago

Read 2 more answers

Help please<br> what is<br>

dsp73

Option A. is correct for the given condition.

Lets solve it through steps of range and functions,

First of all, Solve the equation:
$f(x) = |x|+5$
$= > x = -5$ (1)

$= > x = 5$ (2)

So these would be the ranges of X in between 5 and -5.

Hence option A. $R{f(x)eR [f(x) < 5}$ is correct.

Learn more about range and functions on:

https://brainly.ph/question/10400053

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1 year ago

After school, Hugo helps out at a bunny shelter called Hoppy's Home. He cleans cages and feeds all 8 bunnies at the shelter. In

amm1812

Answer:

25.3

1_ draw a triangle

the shortest side is a which will be 8(bunnies)

diagonal will be c ( what you need to find )

the last side will be b.

so the equation is a2+b2=c2 ( 2=squared)

that means..... 8x8+24x24=c

8x8=64

24x24=576

then add

576+64=640

the find square root

√640=25.2982212813

simplify to 25.3

you know your answer is correct because c is always the biggest side

5 0

2 years ago

Determine whether the following series converge or diverge

Mars2501 [29]

An alternating series $\sum\limits_n(-1)^na_n$ converges if $|(-1)^na_n|=|a_n|$ is monotonic and $a_n\to0$ as $n\to\infty$ . Here $a_n=\dfrac1{\ln(n+1)}$ .

Let $f(x)=\ln(x+1)$ . Then $f'(x)=\dfrac1{x+1}$ , which is positive for all $x>-1$ , so $\ln(x+1)$ is monotonically increasing for $x>-1$ . This would mean $\dfrac1{\ln(x+1)}$ must be a monotonically decreasing sequence over the same interval, and so must $a_n$ .

Because $a_n$ is monotonically increasing, but will still always be positive, it follows that $a_n\to0$ as $n\to\infty$ .

So, $\sum\limits_n(-1)^na_n$ converges.

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2 years ago