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1 year ago

Triangle QRS is to be dilated using the rule D Subscript P, three-fourths.

Mathematics

1 answer:

zaharov [31]1 year ago

5 0

The distance from the center of dilation, P, to.the image vertice S' is; 6 units.

<h3>What is the distance from the center of dilation, P, to the image S'?</h3>

It follows from the task content that the center of dilation of the triangle QRS is point P and the length of segment PS in the pre-image is; 8 units.

Hence, since the dilation factor as given in the task content is; three-fourths, it therefore follows that the distance of point P to S' in the image is; (3/4) × 8 = 6units.

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