Answer:
53
Step-by-step explanation:
i used an angle of 45 degrees.
Distance from ground = 3feets
Angle = 45⁰
U is the initial velocity = 80ft/sec
g = 32
The question wants us to vfind maximum height
We have
r(t) = (80cos45⁰)ti + [3 + 80sin45⁰]t - 0.5(32)t²
We know cos 45 is also sin45 = 1/√2
r(t) = (40√2)ti + [3+40√2]t - 16t²
When we differentiate with respect to t:
r'(t) = (40√2)i + (40√2 - 32t)
= 40√2 =32t
t = 40√2/32
t= 20√2/16
We put the value of t into (3 + 40√2)t -16t²
When we substitute and simplify this we have
3 + 56.57 + 1.77 -16 +8
= 53.34
Which is approximately 53.
Answer:
D
Step-by-step explanation:
Using the sine ratio in the right triangle
noting that sin45° =
← exact value
sin45° =
= 
Multiply both sides by h, then
h ×
= 8
Multiply both sides by 
h = 8
→ D
Answer:

Explanation:
Slope-intercept form formula:

For this formula we need the slope to find the slope use the slope formula:

Plug in the two points (1,-3) and (3,1)

=2
the slope is 2
Now use the slope-interpect formula and plug in the slope (m)

plug in one point I'll use (3,1)

1 = 6 +b
1-6=6-6+b
-5 = b
The equation would be:
The answer to your question is 45 ✌️
Answer:
638
Step-by-step explanation:
its 638, not 639 because its above 638.5