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Gemiola [76]
2 years ago
15

Eli claims that the product of 6 superscript 5 and 5 superscript negative 3 is 6 squared. which explains whether eli is correct?

Mathematics
1 answer:
____ [38]2 years ago
6 0

Answer:

Eli is incorrect. He added the exponents even though the bases are not the same.

Step-by-step explanation:

6^5 * 5^-3 = 6^2

5^-3 = 1/5^3 = 1/125

6^5 = 7776

7776*1/125 = 7776/125 = 62.2 approximately

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the value of b is 3

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3 years ago
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Which of the following is true about the right triangle?
katrin2010 [14]

Option 1. cos (a) = \frac{3}{5}, option 3. sin (a) = \frac{4}{5}, and option 5. tan (a) = \frac{4}{3} are true about the right triangle.

Step-by-step explanation:

Step 1:

According to the Pythagorean theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Here the hypotenuse measures 15 units. Assume the other side measures x.

15^{2} = x^{2} +9^{2} , x^{2} = 15^{2} -9^{2} .

x^{2} = 144, x= 12.

Step 2:

sin \theta = \frac{oppositeside}{hypotenuse} ,cos \theta = \frac{adjacentside}{hypotenuse} , tan \theta = \frac{oppositeside}{adjacentside}.

For angle A, the opposite side is 12 units long, the adjacent side is 9 units long and the hypotenuse is 15 units long.

sin (a) = \frac{12}{15} ,cos(a) = \frac{9}{15} , tan(a) = \frac{12}{9}.

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So option 1. cos (a) = \frac{3}{5}, option 3. sin (a) = \frac{4}{5}, and option 5. tan (a) = \frac{4}{3} are true about the right triangle.

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2. Asymptotes:

f(x)=\dfrac{x-3}{x^2-2x-3}=\dfrac{x-3}{(x-3)(x+1)}=\boxed{\dfrac{1}{x+1}}

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soldier1979 [14.2K]

Answer:

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Answer:

angle CBE=15 degrees

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so angles CBB and CBE are equal

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angle CBE=15 degrees

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