The number of miles in day at which the rental cost for the company A and Company B are the same is 200 miles
The Company A rented the truck for $40 a day plus $0.40 per miles
The expression will be
40+0.40x
Where x is the number of miles
The company B rented the truck for $20 a day plus $0.50 per miles
20+0.50x
To find the number of miles in a day at which the rental costs for Company A and Company B are the same, the linear equation will be
40+0.40x = 20+0.50x
40-20 = 0.50x-0.40x
0.1x = 20
x = 200 miles
Hence, the number of miles in day at which the rental cost for the company A and Company B are the same is 200 miles
Learn more about linear equation here
brainly.com/question/13738061
#SPJ1
y=(-2/5)x + 6
Step-by-step explanation:
y-6= (-2/5)x or y=(-2/5)x + 6
Answer:
<h3>100</h3>
Step-by-step explanation:
Let the number we are looking for be x. If Jack divided 1,826.5 by the number to get a quotient of 18.265, to get the number we will solve the equation;
1,826.5/x = 18.265
Cross multiply
1826.5 = 18.265x
Divide both sides by 18.265
18.265x = 1826.5
18.265x/18.625 = 1826.5/18.625
x = 100
Hence Jack divide 1,826.5 by 100 to get a quotient of 18.265
Answer:
$14722.14
Step-by-step explanation:
We are given that
In 2015
The value of jewel=$17500
Rate of appreciation, r=2.5%
We have to find the initial value of the jewel when it was first bought.
Time, n=7 years
Final value=
Using the formula
Initial value=$14722.14
Hence, the the initial value of the jewel when it was first bought=$14722.14
