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2 years ago

15

Which situation below has a negative correlation?

1 answer:

Schach [20]2 years ago

7 0

Which situation below has a negative correlation?

The younger the child, the more sleep they need.

<em>*100% CORRECT ANSWERS (SEE ATTACHMENTS)</em>

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POINTS!!! PLS COME AND LOOK!!! I NEED YOU GENIUSES!!! I WILL GIVE BRAINLIEST!!!!! AT LEAST COME AND LOOK!!!! WILL FOREVER BE GRE

iris [78.8K]

Answer:

Step-by-step explanation:The absoulte inequalities will have all real solutions asa solution so A, B, AND C all apply.

The relations on the domain of the equation are, C, AND A.

3 0

3 years ago

Find the remainder when the function is <br>

prisoha [69]

according to the question

3x-1=0

3x=1

x=⅓

so

f(x)=18x³+x-1

f(⅓)=18.(⅓)³+⅓-1

f(⅓)=18.⅓.⅓.⅓+⅓-1

f(⅓)=6.⅑+⅓-1

f(⅓)=⅔+½-1

f(⅓)=0

<h3>therefore</h3><h3> the remainder is 0</h3>

4 0

2 years ago

What is the ratio of the area of the inner square to the area of the outer square?

Anastasy [175]

Answer:

$\frac{(a-b)^2+b^2}{a^2}$

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

$=\sqrt{(a-b-0)^2+(0-b)^2}$

$=\sqrt{(a-b)^2+b^2}$

Thus the area of the inner square = (side)²

$=(\sqrt{(a-b)^2+b^2})^2$

$=(a-b)^2+b^2\text{ square cm}$

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

$=\sqrt{(a-0)^2+0^2}$

$=\sqrt{a^2}=a$

Thus, the area of the outer square = (side)²

$=a^2\text{ square cm}$

Hence, the ratio of the area of the inner square to the area of the outer square

$=\frac{(a-b)^2+b^2}{a^2}$

4 0

2 years ago

Read 2 more answers

Find the area and the circumference of a circle with the radius 3 ft.Use 3.14 for pi

Lilit [14]

ANSWER

• Circumference: 18.84 ft

,

• Area: 28.26 ft²

EXPLANATION

The circumference of a circle of radius r is,

$C=2\pi r$

In this case, the radius is r = 3 ft and we have to use 3.14 for π,

$C=2\cdot3.14\cdot3ft=18.84ft$

Hence, the circumference of this circle is 18.84 feet.

The area of a circle of radius r is,

$A=\pi r^2$

In this case, r = 3 ft and π = 3.14,

$A=3.14\cdot3^2ft^2=28.26ft^2$

Hence, the area of this circle is 28.26 square feet.

6 0

10 months ago

Suppose x=c1e−t+c2e3tx=c1e−t+c2e3t. Verify that x=c1e−t+c2e3tx=c1e−t+c2e3t is a solution to x′′−2x′−3x=0x′′−2x′−3x=0 by substitu

Harrizon [31]

The correct question is:

Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)

Answer:

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

Step-by-step explanation:

We need to verify that

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

We differentiate

x = c1e^(-t) + c2e^(3t)

twice in succession, and substitute the values of x, x', and x'' into the differential equation

x''- 2x' - 3x = 0

and see if it is satisfied.

Let us do that.

x = c1e^(-t) + c2e^(3t)

x' = -c1e^(-t) + 3c2e^(3t)

x'' = c1e^(-t) + 9c2e^(3t)

Now,

x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]

= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)

= 0

Therefore, the differential equation is satisfied, and hence, x is a solution.

4 0

2 years ago