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Pani-rosa [81]
3 years ago
6

3. Graph each equation. a. 2x + 3y = 12 b. x=7

Mathematics
1 answer:
Effectus [21]3 years ago
5 0

Answer:

The first pic is for 2x +3y = 12 and the second is for x=7

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10x - 6y = 30

Step-by-step explanation:

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How do you express the ratio 3.5 : 2.5 in its simplest form?
marishachu [46]

Answer:

2.5×2=5

3.5×2=7

RATIO OF 2.5 AND 3.5 IS EQUAL TO 5:7

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Step-by-step explanation:

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Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant
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The chain rule states that

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}

Since \ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2), you have

\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}
\dfrac{\partial w}{\partial x}=\dfrac y{x^2+y^2+z^2}
\dfrac{\partial w}{\partial z}=\dfrac z{x^2+y^2+z^2}

and

\dfrac{\mathrm dx}{\mathrm dt}=\cos t
\dfrac{\mathrm dy}{\mathrm dt}=-\sin t
\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t

Also, since x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t, the derivative is

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\sin t\cos t}{\sec^2t}-\dfrac{\sin t\cos t}{\sec^2t}+\dfrac{\tan t\sec^2t}{\sec^2t}
\dfrac{\mathrm dw}{\mathrm dt}=\tan t
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3 years ago
E/3=7. please can some one help
RUDIKE [14]

Answer:

e=21

Step-by-step explanation:

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Read 2 more answers
What is the equator of 40,075,000
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I'm not even that high level sorry
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