BC = a
AC = b
ACB = C
To find the area of such triangle we are going to use the formula;
1/2 * a * b * sine C
Substitute values.
1/2 * 4 * 4 * sine 45
= 5.65^2
Therefore the area of the triangle is 5.65^2
Answer:
STEP
1
:
Equation at the end of step 1
(5r2 - 14r) + 8
Step-2 : Find two factors of 40 whose sum equals the coefficient of the middle term, which is -14 .
-40 + -1 = -41
-20 + -2 = -22
-10 + -4 = -14 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and -4
5r2 - 10r - 4r - 8
Step-4 : Add up the first 2 terms, pulling out like factors :
5r • (r-2)
Add up the last 2 terms, pulling out common factors :
4 • (r-2)
Step-5 : Add up the four terms of step 4 :
(5r-4) • (r-2)
Which is the desired factorization
Final result :
(r - 2) • (5r -4)
Answer:
I don't know
Step-by-step explanation:
Answer:
let length be x and breadth be y
by question
L=4×1/2×B
L = 2B
now
Area of rectangle=L×B
2B ×B
2B^2
Is it correct? ,I actually tried to solve it
