Answer:
Y' = 360ex+ 30e
Step-by-step explanation:
Y=e×6x×(6x+1) × 5
y'= d/dx (e×6x ×(6x+1)×5)
y'=d/dx(30ex ×(6x+1))
y'=d/dx(180ex^2 + 30ex)
y'=d/dx(180ex^2) + d/dx (30ex)
Calculate the derivative
y'=180e×2x +30e
y'=360ex+30e
The answer is D (y+10)(y-6)
because
Answer:
Since we know that ABCD ~ EFGH, we have the ratios:
EF/AB = GH/CD
=> 0.4/1.2 = x/1.8
=> x = (1.8 . 0.4)/1.2 = 0.6
So x = 0.6
A - area of a trapezoid;
a, b - two bases.
A = h * ( a + b ) / 2 / * 2 ( we have to multiply both sides by 2 )
2 A = h *( a + b )
2 A = h a + h b
h b = 2 A - h a
b = ( 2 A - h a ) / h
b = 2 A/h - a
Answer: D )
Answer:
z1 + z2 = 3
Step-by-step explanation:
Since we are given z1 = 2 + √(3)i and z2 = 1 – √(3)i. The sum of z1 + z2 would be:
(2 + √(3)i) + (1 – √(3)i) = 2 + √(3)i + 1 – √(3)i = 2 + 1 + √(3)i – √(3)i = 3
Hence, z1 + z2 = 3.
