Your teacher asked you to represent 3 more than 8 multiplied by a number T as an expression
(3+8)t = 11t
Answer:
426.9 Km²
Step-by-step explanation:
The shaded area is the area of the triangle subtract the area of the circle.
Area of triangle = 0.5 bh ( b is the base and h the perpendicular height )
Here b = 40 and h = 27, thus
Area = 0.5 × 40 × 27 = 20 × 27 = 540 Km²
Area of circle = πr² ← r is the radius
Here the diameter is 12, thus radius = 12 ÷ 2 = 6
Area = π × 6² = 36π ≈ 113.1 Km²
Shaded area = 540 - 113.1 = 426.9 Km²
Answer:
Rs 120.
Step-by-step explanation:
10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price
-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2
[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2
0.75[CP+10]=0.85[CP-2]
0.75CP+7.5=0.85CP-1.7
0.85CP-0.75CP=-1.7–7.5=9.2
0.10CP=9.2; CP=9.2/0.10
CP=Rs 92 Cost Price of pen
10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)
From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92
Set CP of Eq 1=CP of Eq 2:
CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;
0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12
0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)
Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.
Answer:
[C] -1
Explanation:
3 - 2x = 5
Subtract 3 from both sides
3 - 2x - 3 = 5 - 3
Simplify
-2x = 2
Divide both sides by -2
-2x / -2 = 2 / -2
x = -1