Someone please please help. I have to submit this is about 15 minutes

The ratio of the side lengths of a quadrilateral is 3:3:5:8, and the perimeter is 380cm. What is the measure of the longest side

castortr0y [4]

Answer:

160

Step-by-step explanation:

Add the ratios together to get the sum of them is 19. Since the perimeter is 380, divide 380 by 19 to get 20.

The shortest side is 3(20) = 60,

the next side is 5(20) = 100, and

the longest side is 8(20) = 160

3 0

3 years ago

How many solutions does this linear system have?<br> Y=-1/2x +4x+2y=-8

Vadim26 [7]

Answer: theres no solution

7 0

3 years ago

What the answer guys?

Inga [223]

I dont understand what you mean by whats the answer. please if you can kindly place a question, then maybe i will be able to help you. please and thank you.

3 0

3 years ago

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

4 years ago

Select the correct answer.

Varvara68 [4.7K]

Answer:

OB.

Step-by-step explanation:

you first find the common denominator of the two fractions. then u start dividing each denominator into the common denominator u chose and multiplying the answer with the numerator

8 0

3 years ago

Someone please please help. I have to submit this is about 15 minutes​

Someone please please help. I have to submit this is about 15 minutes