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fenix001 [56]
2 years ago
8

Janet solves this equation

Mathematics
1 answer:
mezya [45]2 years ago
8 0

Of Janet’s two solutions, both x=5 and x=-2 are correct because both x=-2 and x=5 are extraneous solutions

<h3>Logarithmic function</h3>

Given the log function expressed as:

log(x-3) + logx=1

According to the law of logarithm, addition becomes product to have:

log x(x -3) = log₁₀10

x² - 3x = 10

x² - 3x -10 = 0
x² - 5x + 2x - 10 = 0
x(x-5) + 2(x-5) = 0
(x+2)(x-5)=0

x = -2 and 5

Of Janet’s two solutions, both x=5 and x=-2 are correct because both x=-2 and x=5 are extraneous solutions

Learn more on logarithm here: brainly.com/question/25710806

#SPJ1

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The first step in solving the quadratic equation -5x^2+8=133 is to subtract 1.)2 from each same side
Bumek [7]
Try to get x by itself
so minus 8 from both sides

you end up with 5x^2=125

answer is 3rd option
7 0
3 years ago
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What is the slope of line segment 2 ?
Zolol [24]

Answer:

-4,3

Step-by-step explanation:

The rise goes down by 4 making it negative and over by three making it -4,3

5 0
3 years ago
The radius of a right circular cylinder is increasing at the rate of 7 in./sec, while the height is decreasing at the rate of 6
Arlecino [84]

Answer:

\approx \bold{6544\ in^3/sec}

Step-by-step explanation:

Given:

Rate of change of radius of cylinder:

\dfrac{dr}{dt} = +7\ in/sec

(This is increasing rate so positive)

Rate of change of height of cylinder:

\dfrac{dh}{dt} = -6\ in/sec

(This is decreasing rate so negative)

To find:

Rate of change of volume when r = 20 inches and h = 16 inches.

Solution:

First of all, let us have a look at the formula for Volume:

V = \pi r^2h

Differentiating it w.r.to 't':

\dfrac{dV}{dt} = \dfrac{d}{dt}(\pi r^2h)

Let us have a look at the formula:

1.\ \dfrac{d}{dx} (C.f(x)) = C\dfrac{d(f(x))}{dx} \ \ \ (\text{C is a constant})\\2.\ \dfrac{d}{dx} (f(x).g(x)) = f(x)\dfrac{d}{dx} (g(x))+g(x)\dfrac{d}{dx} (f(x))

3.\ \dfrac{dx^n}{dx} = nx^{n-1}

Applying the two formula for the above differentiation:

\Rightarrow \dfrac{dV}{dt} = \pi\dfrac{d}{dt}( r^2h)\\\Rightarrow \dfrac{dV}{dt} = \pi h\dfrac{d }{dt}( r^2)+\pi r^2\dfrac{dh }{dt}\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2r \dfrac{dr }{dt}+\pi r^2\dfrac{dh }{dt}

Now, putting the values:

\Rightarrow \dfrac{dV}{dt} = \pi \times 16\times 2\times 20 \times 7+\pi\times 20^2\times (-6)\\\Rightarrow \dfrac{dV}{dt} = 22 \times 16\times 2\times 20 +3.14\times 400\times (-6)\\\Rightarrow \dfrac{dV}{dt} = 14080 -7536\\\Rightarrow \dfrac{dV}{dt} \approx \bold{6544\ in^3/sec}

So, the answer is: \approx \bold{6544\ in^3/sec}

3 0
3 years ago
Exponents of the multiple 3
nlexa [21]

I believe you are referring to exponents that have a multiple of three. If so any number * three is a valid exponent in your case.

4 0
3 years ago
PLZ HELP!<br>dont just answer something random for points:)tysm​
sergiy2304 [10]

Answer:

4(x^{2} -4)^{2} -76

Step-by-step explanation:

Take out 4:

4(x^2-8x)-12

=4(x^2-8x+16-16)-12

=4(x^2-8x+16)-64-12

=4(x^2-4)^2 - 76

=4(x^{2} -4)^{2} -76

6 0
3 years ago
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