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AleksandrR [38]
3 years ago
11

What values of x will satisfy the inequality 4x + 2 > 10?

Mathematics
2 answers:
mart [117]3 years ago
5 0

Answer:

x > 2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Property

Step-by-step explanation:

<u>Step 1: Define</u>

4x + 2 > 10

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Subtract 2 on both sides:                    4x > 8
  2. Divide 4 on both sides:                        x > 2

Here we see that any value <em>x</em> greater than 2 would work as a solution to the inequality.

patriot [66]3 years ago
4 0

Answer:

x > 2

Step-by-step explanation:

4x + 2 > 10

Subtract 2  from both sides;

4x > 8

Divide both sides by 4;

x > 2

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decreases

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If the discriminant of an equation is zero, which of the following is true of the
miss Akunina [59]

Answer:

Step-by-step explanation:

if the discriminate is 0, it means that both roots are the same. Not only that, but it also means that the roots are real. I would pick D, but realize that that is the expected answer and the answer could be B, depending on how the person writing the problem thinks about it.

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The value of 8y 2 –5y +1 when y= 1 is …………​
ELEN [110]

Answer:

4

Step-by-step explanation:

8(1)^2 -5(1) +1

8(1) -5(1) +1

8 -5 +1

4

4 0
3 years ago
Please help?
Mazyrski [523]

Answer:

23\sqrt{3}\ un^2

Step-by-step explanation:

Connect points I and K, K and M, M and I.

1. Find the area of triangles IJK, KLM and MNI:

A_{\triangle IJK}=\dfrac{1}{2}\cdot IJ\cdot JK\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 2\cdot 3\cdot \dfrac{\sqrt{3}}{2}=\dfrac{3\sqrt{3}}{2}\ un^2\\ \\ \\A_{\triangle KLM}=\dfrac{1}{2}\cdot KL\cdot LM\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 8\cdot 2\cdot \dfrac{\sqrt{3}}{2}=4\sqrt{3}\ un^2\\ \\ \\A_{\triangle MNI}=\dfrac{1}{2}\cdot MN\cdot NI\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 3\cdot 8\cdot \dfrac{\sqrt{3}}{2}=6\sqrt{3}\ un^2\\ \\ \\

2. Note that

A_{\triangle IJK}=A_{\triangle IAK}=\dfrac{3\sqrt{3}}{2}\ un^2 \\ \\ \\A_{\triangle KLM}=A_{\triangle KAM}=4\sqrt{3}\ un^2 \\ \\ \\A_{\triangle MNI}=A_{\triangle MAI}=6\sqrt{3}\ un^2

3. The area of hexagon IJKLMN is the sum of the area of all triangles:

A_{IJKLMN}=2\cdot \left(\dfrac{3\sqrt{3}}{2}+4\sqrt{3}+6\sqrt{3}\right)=23\sqrt{3}\ un^2

Another way to solve is to find the area of triangle KIM be Heorn's fomula, where all sides KI, KM and IM can be calculated using cosine theorem.

7 0
3 years ago
Tristan is an administrator for a private nonprofit college and read a surprising statistic that 74% of graduates from private n
STatiana [176]

Answer: H_0: p=0.74\\\\ H_a:p

Step-by-step explanation:

Let p be the population proportion for the graduates from private nonprofit colleges in the region had at least one outstanding student loan at the time of graduation.

Given : Tristan is an administrator for a private nonprofit college and read a surprising statistic that 74% of graduates from private nonprofit colleges in the region had at least one outstanding student loan at the time of graduation.

i.e. p=0.74

He believes that percentage is high and claims that the proportion of graduates at his college is less than the regional rate.

i.e.  p

Since, the null hypothesis is a statement which always takes equal sign or generally shows " no difference " where as alternative hypothesis takes unequal signs.

Then, the null and alternative hypotheses for this hypothesis test :-

H_0: p=0.74\\\\ H_a:p

6 0
3 years ago
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