What is the slope of a line that is perpendicular to the line y = 8x + 5?
1 answer:
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For this case, we find the equation of the line, for this we look for points where the line passes:
We found the slope:
Thus, the equation of the line is:
We substitute a point to find "b":
Finally:
Now, the domain is given by all the values for which the function is defined.
It is observed that "x" can take any value, that is, it is defined for all real numbers.
Answer:
Option A
Answer:
Step-by-step explanation:
Given: ∠ DEF
To construct: ∠TSZ ≅ ∠DEF
Construction: Consider the attachment
Step-01: Draw a line XY and choose a point S on it as a vertex of the required angle. Further marks point T such that DE = ST
Step-02: Take an arc AB from point E in ∠DEF of any length and draw at point S which cuts at point P on XY line.
Step-03: Take another arc of length AB from point B in ∠DEF and draw from point P which cuts to the previous arc at Q.
Step-04: Now, join the point SQ and extend up to Z such that EF = SZ
Hence, ∠ TSZ will be the required congruent constructed angle to∠DEF
