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mario62 [17]
2 years ago
13

What is the slope of a line that is perpendicular to the line y = 8x + 5?

Mathematics
1 answer:
hoa [83]2 years ago
5 0

Answer . m= -1/8

Step-by-step explanation:

The perpendicular slope is the negative reciprocal. Meaning that the numerator and denominator are switched and the sign of the slope becomes the opposite. (if the slope was -8, then the perpendicular slope would be 1/8)

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Solve for x. Show each step of the solution. 4.5(4 − x ) + 36 = 202 − 2.5(3x + 28)
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Step-by-step explanation:


5 0
3 years ago
Is there any way to post images on your questions?
AysviL [449]

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7 0
3 years ago
In the basketball game, Rachel scored 6 points less than twice the number of points Trina scored. Together they scored 36 points
Vesnalui [34]

Answer:

36=2x-6

Step-by-step explanation:

36=total

2x= Trina

6= Rachel

5 0
3 years ago
What is the probability that a random person who tests positive for a certain blood disease actually has the disease, if we know
xeze [42]

Answer:

Step-by-step explanation:

Hello!

Any medical test used to detect certain sicknesses have several probabilities associated with their results.

Positive (test is +) ⇒ P(+)

True positive (test is + and the patient is sick) ⇒ P(+ ∩ S)

False-positive (test is + but the patient is healthy) ⇒P(+ ∩ H)

Negative (test is -) ⇒ P(-)

True negative (test is - and the patient is healthy) ⇒ P(- ∩ H)

False-negative (test is - but the patient is sick) ⇒ P(- ∩ S)

The sensibility of the test is defined as the capacity of the test to detect the sickness in sick patients (true  positive rate).

⇒ P(+/S) =<u> P(+ ∩ S)  </u>

                    P(S)

The specificity of the test is the capacity of the test to have a negative result when the patients are truly  healthy (true negative rate)

⇒ P(-/H) =<u> P(- ∩ H)  </u>

                   P(H)

For this particular blood disease the following probabilities are known:

1% of the population has the disease: P(S)= 0.01

95% of those who are sick, test positive for it: P(+/S)= 0.95 (sensibility of the test)

2% of those who don't have the disease, test positive for it: P(+/H)= 0.02

The probability of a person having the blood sickness given that the test was positive is:

P(S/+)= <u> P(+ ∩ S)  </u>

                P(+)

The first step you need to calculate the intersection between both events + and S, for that you will use the information about the sickness prevalence in the population and the sensibility of the test:

P(+/S) =<u> P(+ ∩ S) </u>

                 P(S)

P(+/S)* P(S)  = P(+ ∩ S)  

P(+ ∩ S) = 0.95*0.01= 0.0095

The second step is to calculate the probability of the test being positive:

P(+)=  P(+ ∩ S) +  P(+ ∩ H)

Now we know that 1% of the population has the blood sickness, wich means that 99% of the population doesn't have it, symbolically: P(H)= 0.99

Then you can clear the value of P(+ ∩ H):

P(+/H) =<u> P(+ ∩ H) </u>

                 P(H)

P(+/H)*P(H)  = P(+ ∩ H)

P(+ ∩ H) = 0.02*0.99= 0.0198

Next you can calculate P(+):

P(+)=  P(+ ∩ S) +  P(+ ∩ H)= 0.0095 + 0.0198= 0.0293

Now you can calculate the asked probability:

P(S/+)= <u> P(+ ∩ S)  </u> =<u> 0.0095 </u>= 0.32

                P(+)        0.0293

I hope it helps!

                 

                 

6 0
2 years ago
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lakkis [162]
Easy multiply the first number and do keep change flip 
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3 years ago
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