Graph a system of equations to solve log (−5.6x + 1.3) = −1 − x. Round to the nearest tenth.
1 answer:
From the least to the greatest, the solutions are x ≈ -2.1 and x ≈ 0.2
the answers are -2.1 and 0.2.
<h3>What is a linear equation?</h3>It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have two systems of the equation:
y = log (−5.6x + 1.3)
y = −1 − x
After plotting the above equation on the graph we will see two intersections point:
(-2.12, 1.12) and (0.221, -1.221)
So the least value is x = -2.12 ≈ -2.1
The greatest value is x = 0.221 ≈ 0.2
Thus, from the least to the greatest, the solutions are x ≈ -2.1 and x ≈ 0.2
the answers are -2.1 and 0.2.
Learn more about the linear equation here:
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Answer:
The probability of using one or the other is 36%
Step-by-step explanation:
For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:
Probability of passing Professor Jones math class = 64% =0,64
P(J) = 0.64
Probabiliry of passing Professor Smith's physics class = 32% =0.32
P(S) = 0.32
Probability of passing both is = 30% = 0.30
P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram
We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:
P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%
If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.
