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Galina-37 [17]
4 years ago
14

What is the simplified expression for 3^3 . 3^3/3^4

Mathematics
1 answer:
jeka57 [31]4 years ago
6 0
The answer is 9 or 3^2.
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Find the distance between -4.3 and 0.8 on a number line as a decimal
evablogger [386]

Answer:

5.1

Step-by-step explanation:

Add 4.3 to 0.8

6 0
3 years ago
Kate and David each have $10. Together they flip a coin 5 times. Every time the coin lands on heads, Kate gives David $1. Every
olga55 [171]

Answer:

4 possible ways this could happen

Step-by-step explanation:

1. $11

2. $12

3. $13

4. $14

hope this was helpful

8 0
3 years ago
The level of CO2 emissions, f(x), in metric tons, from the town of Fairfax x years after they started recording is shown in the
Temka [501]
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.

2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.

3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.

4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.

Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
7 0
3 years ago
Each of 8 samples has a different standard deviation. How many of the 8 samples could be from the same population?
Oduvanchick [21]
What are the choices? Like A<B<C<D?
5 0
3 years ago
Read 2 more answers
Robert plans to make a box-and-whisker plot of the following set of data.
Lunna [17]

Answer:

lower quartile: 18; median: 27; upper quartile: 38

Step-by-step explanation:

The given set of data is

27, 14, 46, 38, 32, 18, 21

Arrange this set of data in numeric order

14,18,21,27,32,38,46

The given set of data has 7 numbers which is odd.

Median in the middle value. The middle value of the data is fourth value which is 27.

Hence, median = 27

Now, the first half of the set of data is

14,18,21

Middle value = 18

Hence, lower quartile = 18

The second half is 32,38,46

Middle value = 38

Hence, uper quartile = 38

Thus, the correct option is

lower quartile: 18; median: 27; upper quartile: 38



4 0
3 years ago
Read 2 more answers
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