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2 years ago

What is the circumference of a circle with a diameter of 5 feet? Use 3.14 for TT.

Mathematics

2 answers:

Brut [27]2 years ago

7 0

$\triangleright$ Hii! $\triangleleft$

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Answer: Circumference = 15.7 ft ✅

Step-by-step explanation:

Do you need to know the circumference of a circle with a diameter of 5 ft? No problem! Luckily, there's a formula to find it! (:

<h3>Circumference</h3>

Let's work out the circumference. This is the formula that is going to help us. $\rightsquigarrow\boldsymbol{C=\pi d}$ C=circumference π=pi d=diameter

<em>Now, stick in the values (note that we can use 3.14 for pi; pi is irrational, so we use 3.14 instead of pi to avoid irrational numbers)</em>

$\boldsymbol{C=3.14\cdot5}$ . Upon simplifying we obtain

$\boldsymbol{C=15.7\;ft}$ . Which is our final answer.

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Hope that this helped! Best wishes.

$\boldsymbol{Reach \quad far. \quad Aim \quad high. \quad Dream \quad big.}$

#StudyWithBrainly (:

PS. Please refer to <em>this </em>link if you want to learn more!! ^^

✨brainly.com/question/1351251?referrer=searchResults

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Anni [7]2 years ago

5 0

Answer: 15.7

Step-by-step explanation:

$C=\pi d\\\\C=5\pi$

Using $\pi=3.14$ , we get $C \approx 5(3.14)=\boxed{15.7 \text{ ft}}$

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Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments

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Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

$\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}$

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

$\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}$

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.