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2 years ago

Can someone help me ?

Mathematics

1 answer:

alexira [117]2 years ago

6 0

Answer:

Can you please show the questions? It's way more easier

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Three to the fourth power.<br> Write the numerical answer only.

irakobra [83]

30000 is the answer I think

8 0

2 years ago

Please help with this<br>

tankabanditka [31]

Answer:

x=3

Step-by-step explanation:

y= -2

4x-3y=18

4x-3(-2)=18

4x-(-6)=18

4x+6=18

4x+6-6=18-6

4x=12

$\frac{4x}{4} = \frac{12}{4}$

x=3

If its helpful ❤❤❤

THANK YOU

6 0

2 years ago

Can somebody help me?

Degger [83]

A percentage
Have a good dayyyyyy

5 0

3 years ago

I need help on this it’s about trig identities

Cerrena [4.2K]

Answer:

The answer to your question is:

Step-by-step explanation:

1.-

$\frac{1 + sin\alpha }{cos\alpha } + \frac{cos\alpha }{1 + sin\alpha } = 2 sec\alpha$

$\frac{(1 + sin\alpha)^{2} + cos^{2} \alpha }{cos\alpha (1 + sin\alpha) }$

$\frac{1 + 2sin\alpha + sin^{2} \alpha+ cos^{2} \alpha }{cos\alpha + sin\alphacos\alpha }$

$\frac{2 + 2sin\alpha }{cos\alpha+ sin\alpha cos\alpha }$

$\frac{2(1 + sin\alpha) }{cos\alpha(1 + sin\alpha ) }$

$\frac{2}{cos\alpha }$

2sec $\alpha$

2.-

sec²x - tanxsecx

$\frac{1}{cos^{2}x } - \frac{sinx}{cosx} \frac{1}{cosx}$

$\frac{1}{cos^{2} x} - \frac{sinx}{cos^{2}x}$

$\frac{1 - sinx}{cos^{2}x }$

$\frac{1 - sinx}{1 - sin^{2}x }$

$\frac{1 - sinx}{(1 - sinx)(1 + sinx)}$

$\frac{1}{1 + sinx}$

3 0

2 years ago

Please help this is due in 20 minutes

Allushta [10]

Answer:

1.SAS, ASA,

2. Not congruent

3.C

4. If you could screenshot the whole page I can give tell you what it is.

3 0

2 years ago