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Mars2501 [29]
3 years ago
7

Can someone help me ?

Mathematics
1 answer:
alexira [117]3 years ago
6 0

Answer:

Can you please show the questions? It's way more easier

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A sports club has 84 members who learned baseball, and 42 of those members also learned basketball. There are 25 students who di
HACTEHA [7]

<em>The table that shows the relative frequency of data is in the below further explanation.</em>

\texttt{ }

<h3>Further explanation</h3>

A set is a clearly defined collection of objects.

To declare a set can be done in various ways such as:

  • With words or the nature of membership
  • With set notation
  • By registering its members
  • With Venn diagrams

\texttt{ }

Multiplying set A x B is by pairing each member of set A with each member of set B.

<u>Example:</u>

<em>A = {1, 2, 3}</em>

<em>B = {a, b}</em>

Then

A x B = {(1, a), (1, b), (2, a), (2, b), (3, a), (3, b)}

\texttt{ }

Union of set A and B ( A ∪ B ) is rewriting each member A and combined with each member B.

Intersection of set A and B ( A ∩ B ) is to find the members that are both in Set A and Set B.

<u>Example:</u>

<em>A = {1, 2, 3, 4}</em>

<em>B = {3, 4, 5}</em>

A ∪ B = {1, 2, 3, 4, 5}

A ∩ B = {3, 4}

Let us now tackle the problem!

\texttt{ }

<em>A sports club has 84 members who learned baseball, and 42 of those members also learned basketball.</em>

\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&\boxed{42}& \\Don't Play Basketball& & \end{array}\right]

\texttt{ }

Number of members who learned baseball but did not learn basketball will be ( 84 - 42 ) = 42 members

\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&42& \\Don't Play Basketball&\boxed{42}& \end{array}\right]

\texttt{ }

<em>There are 25 students who did not learn baseball but learned basketball</em>

\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&42&\boxed{25} \\Don't Play Basketball&42& \end{array}\right]

\texttt{ }

<em>8 students did not learn either baseball or basketball</em>

\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&42&25 \\Don't Play Basketball&42&\boxed{8} \end{array}\right]

\texttt{ }

<em>Total Number of Students = 42 + 42 + 25 + 8 = 117</em>

\texttt{ }

Table of relative frequency

\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&\boxed{\frac{42}{117}}&\boxed{\frac{25}{117}} \\Don't Play Basketball&\boxed{\frac{42}{117}}&\boxed{\frac{8}{117}} \end{array}\right]

\texttt{ }

<h3>Learn more</h3>
  • Mean , Median and Mode : brainly.com/question/2689808
  • Centers and Variability : brainly.com/question/3792854
  • Subsets of Set : brainly.com/question/2000547

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Sets

Keywords: Sets , Venn , Diagram , Intersection , Union , Mean , Median , Mode

8 0
3 years ago
Read 2 more answers
Solve:2x +7=3 show answer and working out
ivolga24 [154]
3-7= -4

2×-4= -2

I think i did that right...
5 0
3 years ago
Read 2 more answers
PLEASE HELP I GIVE THANKS
My name is Ann [436]
For #1 is <em>A </em>because the -5\12 is greater than -2\5
For #2 is <em>C </em>because A is the same as the question and B,D ARE WRONG.
1:- A

2:-C
I HOPE THIS WOULD HELP YOU  THANK YOU
5 0
3 years ago
Water flowed out of a tank at a steady rate. A total of 18 1/2 gallons flowed out of the tank in 4 1/4 hours. Which expression
Alecsey [184]

Answer:

In 1 hour water flowed out = \frac{74}{17}  gallons

Step-by-step explanation:

Given as ,

The quantity of water flowed out of tank =  18 \frac{1}{2} gallons

                                                                   =    \frac{37}{2} gallons

The time spend in flowing water out of tank = 4  \frac{1}{4} hours

                                                                          =    \frac{17}{4} hours

∵ In  \frac{17}{4} hours , water flowed out =  \frac{37}{2}

∴ In    1    hours                           ,  water flowed out = \frac{37\times4}          {17\times2}

So, in 1 hour water flowed out = \frac{74}{17}  gallons Answer

6 0
3 years ago
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Defective components: A lot of 9 components contains 4 that are defective. Two components are drawn at random and tested. Let A
dusya [7]
Umm I have no Idea sorry
8 0
3 years ago
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