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Mars2501 [29]
2 years ago
7

Can someone help me ?

Mathematics
1 answer:
alexira [117]2 years ago
6 0

Answer:

Can you please show the questions? It's way more easier

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Three to the fourth power.<br> Write the numerical answer only.
irakobra [83]
30000 is the answer I think
8 0
2 years ago
Please help with this<br>​
tankabanditka [31]

Answer:

x=3

Step-by-step explanation:

y= -2

4x-3y=18

4x-3(-2)=18

4x-(-6)=18

4x+6=18

4x+6-6=18-6

4x=12

\frac{4x}{4} =  \frac{12}{4}

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If its helpful ❤❤❤

THANK YOU

6 0
2 years ago
Can somebody help me?
Degger [83]
A percentage
Have a good dayyyyyy
5 0
3 years ago
I need help on this it’s about trig identities
Cerrena [4.2K]

Answer:

The answer to your question is:

Step-by-step explanation:

1.-

\frac{1 + sin\alpha }{cos\alpha } + \frac{cos\alpha }{1 + sin\alpha } = 2 sec\alpha

\frac{(1 + sin\alpha)^{2} + cos^{2} \alpha  }{cos\alpha (1 + sin\alpha) }

\frac{1  + 2sin\alpha + sin^{2} \alpha+ cos^{2} \alpha  }{cos\alpha + sin\alphacos\alpha  }

\frac{2 + 2sin\alpha }{cos\alpha+ sin\alpha cos\alpha  }

\frac{2(1 + sin\alpha) }{cos\alpha(1 + sin\alpha ) }

\frac{2}{cos\alpha }

2sec\alpha

2.-

   sec²x - tanxsecx

\frac{1}{cos^{2}x } - \frac{sinx}{cosx} \frac{1}{cosx}

\frac{1}{cos^{2} x} - \frac{sinx}{cos^{2}x}

\frac{1 - sinx}{cos^{2}x }

\frac{1 - sinx}{1 - sin^{2}x }

\frac{1 - sinx}{(1 - sinx)(1 + sinx)}

\frac{1}{1 + sinx}

3 0
2 years ago
Please help this is due in 20 minutes
Allushta [10]

Answer:

1.SAS, ASA,

2. Not congruent

3.C

4. If you could screenshot the whole page I can give tell you what it is.

3 0
2 years ago
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