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Vaselesa [24]
3 years ago
9

A rectangle table is 14 centimeters long and 12 centimeters wide. What is it’s perimeter

Mathematics
1 answer:
djyliett [7]3 years ago
6 0

Answer:

Perimeter = 52 centimeters

Step-by-step explanation:

The perimeter of a rectangle, is the length of all of the sides of a rectangle added together.

Each rectangle has two equal lengths, and two equal widths. Since we know the length is equal to 14, then the two lengths together would be 28. The width is 12, and the two widths together are 24.

Finally we add the 28 and 24 together to find the total perimeter of 52 centimeters.

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The perimeter p of a regular hexagon varies directly with the length l of one side of the hexagon. What is an equation that rela
Oksi-84 [34.3K]
A hexagon has 6 sides, so the perimeter can be calculated as 6 x l. In other words:

P = 6l

I have attached what the graph to this will look like (looks like the graph y = 6x)

4 0
3 years ago
Solve for x. x = log5 1 x =
dezoksy [38]

Answer:

use the calculator to get your answers pls

5 0
3 years ago
HW 7.4/7.5 help mhhhh
Hatshy [7]

Answer:

1. LI=18

2. x=10

3. Yes (Y)

4. Yes (Y)

5. x=15

6. x=18

7. x=8

8. x=6

   y=6.5

Step-by-step explanation:

1. LI/JL=KH/JK

Replacing the given values:

LI/6=21/7

Dividing on the right side of the equation:

LI/6=3

Solving for LI: Multiplying both sides of the equation by 6:

6(LI/6)=6(3)

LI=18


2.TV/VS=RU/US

Replacing the given values:

x/17.5=8/14

Simplifying the fraction on the right side of the equation: Dividing numerator and denominator by 2:

x/17.5=(8/2) / (14/2)

x/17.5=4/7

Solving for x: Multiplying both sides of the equation by 17.5:

17.5(x/17.5)=17.5(4/7)=(17.5/1)(4/7)

Multiplying:

x=(17.5 x 4) / (1 x 7)

x=70/7

Dividing:

x=10


3. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB=15/12=(15/3) / (12/3)→AD/DB=5/4

AE/EC=10/8=(10/2) / (8/2)→AE/EC=5/4

Like AD/DB=5/4=AE/EC → BC is parallel to DE


4. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB= 2DB / DB→AD/DB=2

AE/EC=30 / (AC-AE)=30 / (45-30)=30/15→AE/EC=2

Like AD/DB=2=AE/EC → BC is parallel to DE


5. If JH is a midsegment of triangle KLM:

x=(1/2)(30)

x=15


6. If JH is a midsegment of triangle KLM:

x=2(9)

x=18


7. If JH is a midsegment of triangle KLM: x=8


8. 2x+1=x+7

Solving for x. Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

2x+1-x=x+7-x

Subtracting:

x+1=7

Subtracting 1 both sides of the equation:

x+1-1=7-1

Subtracting:

x=6

2x+1=2(6)+1=12+1→2x+1=13

x+7=6+7→x+7=13


(3y-8)/(y+5)=(2x+1)/(x+7)

(3y-8)/(y+5)=13/13

(3y-8)/(y+5)=1

3y-8=y+5

Solving for y. Grouping the y's on the left side of the equation: Subtracting y both sides of the equation:

3y-8-y=y+5-y

Subtracting:

2y-8=5

Adding 8 both sides of the equation:

2y-8+8=5+8

Subtracting:

2y=13

Dividing both sides of the equation by 2:

2y/2=13/2

Dividing:

y=6.5



3 0
3 years ago
HELP PLEASE
slamgirl [31]

Answer:

\displaystyle 228,8

Step-by-step explanation:

\displaystyle 2\frac{3}{5}\:sleps = 1\:quib \\ \\ 2\frac{3}{5} \times 88 = 228\frac{4}{5} = 228,8

I am joyous to assist you anytime.

8 0
3 years ago
Read 2 more answers
HELP NOW ASAP HURRY i don't got all day!!!!!!!!!!!!!
Anarel [89]

Answer:

15 3/4t^2 + 5 1/4

Explanation:

h(t)=-16t^2+400

We can add 400 then - 64 and show as 8^2

= h(t)=-16t^2+400 - 8^2  

But we also need to change 16t^2;

We divide 64 into 16 = 16/64 =0.25

and show 16t^2 changes by 0.25 = 1/4

15 3/4t^2 + 400-64

Can now look like

15 3/4t^2 + 5 1/4

As 5 1/4 = 64 x 5 1/4 = 336

8 0
3 years ago
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