Answer: the "y=mx+b" form (called the slope-intercept form of the equation of a line).
Explanation: Finding the equation for a line is a common problem in geometry and trigonometry. There are two common situations where you are asked to find the equation for a line: either you'll be provided with one point on the line and the slope of the line, or you'll be provided two points on the line.
The "b" value (called the y-intercept) is where the line crosses the y-axis.
So point (x1, y1) is actually at (0, b)
and the equation becomes:
Start with
y − y1 = m(x − x1)
(x1, y1) is actually (0, b):
y − b = m(x − 0)
Which is:
y − b = mx
Put b on other side:
y = mx + b
Answer:
Explanation:
The osmotic gradient in the kidney typically in the medulla is a process that generates urine that is 5 times more concentrated so as to reduce the loss of water from the body.
The countercurrent multiplication is a process that uses energy to produce the osmotic gradient in the kidney, this process facilitates the reabsorption of water from the tubular fluid. This mechanism moves the sodium chloride from the tubular fluid to the interstitial space of the kidneys. The osmotic gradient can be developed in two ways:
1. The single effect: This involves the transport of sodium chloride from the tubular fluid and moved to the ascending limb then finally to the interstitial fluid. As a result of this, the water moves passively down to the concentration gradient out of the tubular fluid than to the descending limb of the interstitial space, until the equilibrium is achieved.
2. Fluid flow method: The tubular fluid enters into the descending limb. This pushes the fluid into high osmolarity typically down the tube. This way the osmotic gradient develops.
Answer:
right answer is option no c cardiology
Answer:
<u>Flow rate = 16.67 gtts/min rounded to 17 gtts/min</u>
Explanation:
In order to calculate the flow rate, the following formula will be used.
Flow rate (gtts/min) = 
50 mL of fluid in which Ciprofloxacin is dissolved is taken as volume.
<u>KNOWN DATA:</u>
Volume = 50mL
Time = 45 minutes
Drop factor = 15 gtts/mL
Flow rate = unknown
<u>CALCULATION:</u>
Plugging the known values in the formula,
Flow rate (gtts/min) =
Flow rate = 
x 15
<u>Flow rate = 16.67 gtts/min.</u>
