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2 years ago

!! 30 PTS !! Hello, I need some help on this Geometry Area question:

Mathematics

1 answer:

ELEN [110]2 years ago

7 0

You have to multiply 54 times 1.2 and you will get 64.8. So, 64.8 is your area.

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Please Help me solve for x<br> 3x-m=10

Triss [41]

Answer:

x=(10+m)/3

Step-by-step explanation:

3x-m=10

3x=10+m

x=(10+m)/3

8 0

3 years ago

Read 2 more answers

I need help please!!

luda_lava [24]

Answer:

2 remainder 5 ily

Step-by-step explanation:

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2 years ago

A Mercedes can go 78 miles on 3 gallons of gas. How far can it go with a full tank of 16 gallons?

Alex787 [66]

Answer:

416 miles

Step-by-step explanation:

78 divided by 3 = 26

26 x 16 = 416

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2 years ago

Given a data set consisting of 33 unique whole number observations, its five-number summary is:

Lemur [1.5K]

Answer:

given a data set of 33 unique whole number observation,its five number sumary is [16, 29, 40 ,54, 67]

Step-by-step explanation:

The p-th percentile in an ordered (from low to high) data set is a value such that p% of the data is less than that value. The quartiles of a data set are the 25th, 50th and 75th percentiles. (The 25th percentile is usually called the first quartile, the 50th percentile is usually called the median, and the 75th percentile is usually called the third quartile.)

The formula for finding the location (or position) of the (approximate) pth percentile in an ordered (from low to high) data set is

L p=(n+1).p/100

For example, in the data set [2,4,6,8,10,12,14,16,18]

the (approximate) 60th percentile is located at position

L 60=(9+1).60/100=6

that is, the sixth data point (the value 12) is at the (approximate) 60th percentile.(Actually, only 55.6% of the data is below a 12.)

3 0

2 years ago

A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to

melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

$P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}$

Mean of X:

$E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42$

Variance of X:

$E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}$

$var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58$

5 0

3 years ago