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Mashutka [201]
3 years ago
7

!! 30 PTS !! Hello, I need some help on this Geometry Area question:

Mathematics
1 answer:
ELEN [110]3 years ago
7 0
You have to multiply 54 times 1.2 and you will get 64.8. So, 64.8 is your area. 
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What is 2,400 milliliters converted into liters
BARSIC [14]

Answer:

2.4 liters

Step-by-step explanation:

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3 years ago
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PLEASEE HELPP ANYONE
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Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩
NISA [10]

Answer:

\theta = 108.29

Step-by-step explanation:

Given

u =

v =

Required:

Calculate the angle between u and v

The angle \theta is calculated as thus:

cos\theta = \frac{u.v}{|u|.|v|}

For a vector

A =

A = a * b

cos\theta = \frac{u.v}{|u|.|v|} becomes

cos\theta = \frac{.}{|u|.|v|}

cos\theta = \frac{2*6+4*-7}{|u|.|v|}

cos\theta = \frac{12-28}{|u|.|v|}

cos\theta = \frac{-16}{|u|.|v|}

For a vector

A =

|A| = \sqrt{a^2 + b^2}

So;

|u| = \sqrt{2^2 + 6^2}

|u| = \sqrt{4 + 36}

|u| = \sqrt{40}

|v| = \sqrt{4^2+(-7)^2}

|v| = \sqrt{16+49}

|v| = \sqrt{65}

So:

cos\theta = \frac{-16}{|u|.|v|}

cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}

cos\theta = \frac{-16}{\sqrt{2600}}

cos\theta = \frac{-16}{\sqrt{100*26}}

cos\theta = \frac{-16}{10\sqrt{26}}

cos\theta = \frac{-8}{5\sqrt{26}}

Take arccos of both sides

\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})

\theta = cos^{-1}(\frac{-8}{5 * 5.0990})

\theta = cos^{-1}(\frac{-8}{25.495})

\theta = cos^{-1}(-0.31378701706)

\theta = 108.288386087

<em></em>\theta = 108.29<em> (approximated)</em>

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2 years ago
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julsineya [31]
The answer is(4 -3.5x-15)hope this can help
4 0
3 years ago
10) Use the equation x2 + 8x = 9 to answer the following questions (1 point for each part, 2 points total). .
GREYUIT [131]

Answer:

i might be wrong but i think its 10

Step-by-step explanation:

x2+8x=9

collet terms

10x=9

divide both side by 10

x = 9/10

alternative form

x = 0.9

8 0
3 years ago
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