Use the drop-down menus to determine the best estimate for 5,984 ÷ 32. Then find the quotient.

Mathematics

1 answer:

katrin [286]2 years ago

3 0

Answer: 5,984 ÷ 32 = 0,187

Ok done. Thank to me :>

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A car was originally purchased in January 2010 for 27000 dollars. The car depreciates at a rate of 18% every year.

Maksim231197 [3]

Answer:

Number of year(n) = 3.4 year (Approx)

Step-by-step explanation:

Given:

Purchase value of car = $27,000

Depreciation rate per year (d) = 18% = 0.18

Future price = half of its original value = $27,000 / 2 = $13,500

Find:

Number of year(n) = ?

Computation:

$Future price =Purchase value(1-d)^n\\\\13,500=27,000(1-0.18)^n\\\\0.5=(0.82)^n\\\\n=3.444(Approx)$

Number of year(n) = 3.4 year (Approx)

5 0

3 years ago

Consider the equation below. Log Subscript 4 Baseline (x 3) = log Subscript 2 Baseline (2 x) Which system of equations can repre

swat32

Equal expressions can be taken equal to an another variable. The system of equations representing the equation is $y = x + 3\\y = 4x + 8$

<h3>What is logarithm and some of its useful properties?</h3>

When you raise a number with an exponent, there comes a result.

Lets say you get

Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows

Some properties of logarithm are:

$log_a(b) = log_a(c) \implies b = c\\\\\log_a(b) + log_a(c) = log_a(b \times c)\\\\log_a(b) - log_a(c) = log_a(\frac{b}{c})\\\\log_a(b^c) = c \times log_a(b)\\\\log_b(b) = 1\\\\ log_a(b) + log_b(c) = log_a(c)$

Log with base e = 2.71828... is written as $\ln(x)$ simply.

Log with base 10 is written as $\log(x)$ simply.

The given equation is:

$\log_4(x+3) = \log_2(2 +x)$

Adding $\log_2(4)$ on both the sides, we get:

$\log_2(4) + \log_4(x+3) =\log_2(4) + \log_2(2 +x) \\\\log_2(x + 3) = log_2(4(2+x))\text{\: \: \: (using first and last property listed)}\\\\x+3 = 8+4x = y(say)$