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vladimir2022 [97]
2 years ago
7

A parabola passes through the points (2,8), (6,2), and (8,8). what is the x-coordinate of its vertex?

Mathematics
1 answer:
Flura [38]2 years ago
5 0

The x-value of the vertex of the given parabola is x = 5, so the correct option is b.

<h3>How to get the x-value of the vertex?</h3>

If we define the parabola by f(x), by looking at the table, we can read:

  • f(2) = 8
  • f(6) = 2
  • f(8) = 8

So, notice that:

f(2) = f(8).

Then the x-coordinate of the vertex is the midpoint between 2 and 8.

x = (2 + 8)/2 = 5

The x-value of the vertex of the given parabola is x = 5, so the correct option is b.

If you want to learn more about parabolas:

brainly.com/question/4061870

#SPJ1

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Ind the slope and y intercept of -9x+3y=5
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Remove the brackets using the distributive law for the following: 2(x + 3)
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3 years ago
What irrational number is between 4.47 and 4.48?
shepuryov [24]

Answer: √20 is between 4.47 and 4.48

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5 0
3 years ago
2. Write a quadratic function that has -intercepts (- 3, 0) and (4, 0) and passes through the point (5, 8)
Reptile [31]

Answer:

f(x)=x^2-x-12

Step-by-step explanation:

<u>Quadratic Function</u>

Standard Form of Quadratic Function

The standard representation of a quadratic function is:

f(x)=ax^2+bx+c

where a,b, and c are constants.

When the zeros of f (x1 and x2) are given, it can be written as:

f(x)=a(x-x1)(x-x2)

Where a is a constant called the leading coefficient.

We are given the two roots of f: x1=-3 and x2=4, thus:

f(x)=a(x+3)(x-4)

We also know that f(5)=8, thus:

f(5)=a(5+3)(5-4)=8

Operating:

a(8)(1)=8

Solving:

a=1

The function is:

f(x)=1(x+3)(x-4)

Operating:

\boxed{f(x)=x^2-x-12}

5 0
3 years ago
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