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3 years ago

Rewrite the expression with rational exponents as a radical expression by extending the properties of Internet exponents

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

4 0

Answer:

option a

Step-by-step explanation:

y^7/8 / y^1/4

First we will accommodate the fractions

1/4 = 2/8

y^7/8 / y^2/8

Then we will subtract the exponents of the powers since they have the same base and are dividing

7/8 - 2/8 = 5/8

y^5/8

Finally we pass the 8 as radical root

8√y^5

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1. For the function f(x) = x2, Find the slope of the secant line joining (1,f(1)) and

goblinko [34]

The slope of the line connecting two points (a, b) and (c, d) is

(d - b) / (c - a)

i.e. the change in the y-coordinate divided by the change in the x-coordinate. For a function y = f(x), this slope is the slope of the secant line connecting the two points (a, f(a) ) and (c, f(c) ), and has a value of

(f(c) - f(a) ) / (c - a)

Here, we have

f(x) = x ²

so that

f (1) = 1² = 1

f (1.01) = 1.01² = 1.0201

Then the slope of the secant line is

(1.0201 - 1) / (1.01 - 1) = 0.0201 / 0.01 = 2.01

3 0

3 years ago

Please see the picture .......................

aivan3 [116]

Answer:

Explanation: dont got one

8 0

3 years ago

Read 2 more answers

Please help 20 POINTS problem below

Paraphin [41]

I think your answer would be A?

6 0

3 years ago

Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic t.

lawyer [7]

Using the t-distribution, it is found that the p-value of the test is 0.007.

At the null hypothesis, it is tested if the mean lifetime is not greater than 220,000 miles, that is:

$H_0: \mu \leq 220000$

At the alternative hypothesis, it is tested if the mean lifetime is greater than 220,000 miles, that is:

$H_1: \mu > 220000$ .

We have the standard deviation for the sample, thus, the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem:

$\overline{x} = 226450, \mu = 220000, s = 11500, n = 23$

Then, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{226450 - 220000}{\frac{11500}{\sqrt{23}}}$

$t = 2.69$

We have a right-tailed test(test if the mean is greater than a value), with t = 2.69 and 23 - 1 = 22 df.

Using a t-distribution calculator, the p-value of the test is of 0.007.

A similar problem is given at brainly.com/question/13873630

8 0

2 years ago

Expand and simplify: (-7y - 8) (y - 4)

ZanzabumX [31]

<h2>Simplification</h2>

<h3>Expand and simplify: (-7y - 8) (y - 4)</h3>

To expand an expression, use FOIL method.

<h3>F - First</h3>

Multiply the first term in each expression inside the parentheses.

-7y and y are the first terms in each expression.

(-7y)(y) = -7y²

<h3>O - Outside </h3>

Next is to multiply the terms outside. (The first term in the first expression and the last term in the second expression)

-7y is the first term in the first expression

-4 is the last term of the second expression

(-7y)(-4) = 28y

<h3>I - Inside</h3>

The next step is to multiply the terms inside. (The last term in the first expression and the first term in the last expression)

-8 is the last term in the first expression

y is the first term in the second expression

(-8)(y) = -8y

Last step is to multiply the last term in each expression.

-8 is the last term of the first expression

-4 is the last term of the second expression

(-8)(-4) = 32

Combine all simplified terms.

-7y² + 28y - 8y + 32
-7y + 20y + 32

Answer:

-7y + 20y + 32

Wxndy~~

8 0

1 year ago