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Blababa [14]
3 years ago
12

The Great Pyramid is a square pyramid with a base area of 571,536 ft2 and a height of 48 stories. Each story is approximately 10

feet. Estimate the volume in cubic yards.
Mathematics
1 answer:
RUDIKE [14]3 years ago
4 0
To estimate the volume, you will use the formula for finding volume of a pyramid.

You will need to convert the height, given in feet, to yards.

(48 x 10)/3= 160 yards

You also need to convert the area of the base to square yards.

571536 ft.²/ 9 ft.² (1 square yd)= 63,504 yd.².

V = 1/3 BH, where B is the area of the base.

V = 1/3 x 63504 x 160
V = 3,386880 cubic yards

The approximate volume of The Great Pyramid is 3,386,880 yd.³.
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The Answer is <u>A. 3. :D</u>

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I need help with premetier and area for 7 8 9
SCORPION-xisa [38]

The answers to the three shapes are:

Figure 7; perimeter = 16.2mm, area = 12.64 square mm

Figure 8; perimeter = 15.2inches, area = 9.61 square inches

Figure 9; perimeter = 21.47yards,  area = 16.81 square yards

<h3>What is the perimeter of a shape?</h3>

Perimeter is the outside boundary of a plane shape.

Analysis:

for figure 7, perimeter = s + s + s = 3s = 3(5.4) = 16.2mm

                   Height of triangle = \sqrt{((5.4)^{2} - (2.7)^{2}  } = 4.68

            Area of triangle = 1/2 base x height = 1/2 x 5.4 x 4.68 = 12.64mm^{2}

For figure 8, perimeter = b + b + a = 5.9 + 5.9 + 3.4 = 15.2 inches

                     Height of triangle = \sqrt{(5.9)^{2}  - (1.7)^{2} } = 5.65inches

           Area of triangle = 1/2 base x height = 1/2 x 3.4 x 5.65 = 9.61inches^{2}

For figure 9, perimeter = b + a + c = 8.2 + 4.1 + 9.17 = 21.47yards

           Area of triangle = 1/2 x base x height = 1/2 x 8.2 x 4.1 = 16.81yards^{2}

In conclusion, the perimeter and area of the given shapes are:

Figure 7; perimeter = 16.2mm, area = 12.64 square mm

Figure 8; perimeter = 15.2inches, area = 9.61 square inches

Figure 9; perimeter = 21.47yards,  area = 16.81 square yards

Learn more about perimeter of plane shapes: brainly.com/question/2569205

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The equation of the line would be

y = mx+b 

where m is the slope, b is the y intercept. 

<span>The line will form a triangular region in the first quadrant. Its area would be 1/2 base times height. The height is the y intercept and the base is y intercept divided by slope. Therefore,</span>

A = b^2/2m

At point (2,5)

5 = 2m+b

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<span>find b and use that to find m. Then, you can have the equation of the line.</span>


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