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3 years ago

Find the median of these numbers 5,9,13,7,5,7

Mathematics

1 answer:

Troyanec [42]3 years ago

3 0

Answer:

The mean is 7

Step-by-step explanation:

5,5,7,7,9,13

9-7 is going to get 7

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Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0

2 years ago

1) What is the solution to x - 5 = 27?

Phoenix [80]

X - 5 = 27

Isolate the x, add 5 to both sides (because of equal sign)

x - 5 = 27
x - 5 (+5) = 27 (+5)
x = 27 + 5
x = 32

x = 32 is your answer

hope this helps

3 0

2 years ago

Simplify: − 7( 21 − 16) + 3(9) (24 − 18)

Mekhanik [1.2K]

The answer to the problem is 127

6 0

2 years ago

Read 2 more answers

Can someone help me for 20 points please? Thanks, make sure it is correct!

zzz [600]

Yes what do you need help with

8 0

2 years ago

A school survey reported that

kozerog [31]

The probability that the student has a part-time job, given that they have a cell phone is 5/8

<h3>What is probability</h3>

Probability is the likelihood or chance that an event will occur.

Given the following parameter:

Total student = 80%
Part-time jobs = 45%
Those with both a cell phone and a part-time job = 30%

Student will cellphone only = 80 - 30 = 50%

The probability that the student has a part-time job, given that they have a cell phone is 50/80 = 5/8

Learn more on probability here: brainly.com/question/25870256

6 0

1 year ago