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2 years ago

10

What conic section is drawn by the parametric equations x=csc t and y cot?

1 answer:

Vanyuwa [196]2 years ago

3 0

If we take the square of x and square of y and then subtract them:
(csc t)²-(cot t)²=1 ( this eq. gets from basic identity
x²-y²=1......a 1+cot²x=csc²x)

equation 'a' represent the equation of hyperbola which is (x²/a²)-(y²/b²) =1 with given conditions( a=1,b=1)

So, option D is correct

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creativ13 [48]

Answer:

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Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

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s ---> the arc length of sector

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we know that

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solve for r

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step 2

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substitute the value of r

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step 3

we know that

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so

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Let

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substitute the value of r

$A=\frac{(\frac{18}{2+\theta})^2\theta}{2}$

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Convert to function notation

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