Question

What conic section is drawn by the parametric equations x=csc t and y cot?

Answer 1

If we take the square of x and square of y and then subtract them:
                         (csc t)²-(cot t)²=1                      ( this eq. gets from basic identity 
                               x²-y²=1......a                                               1+cot²x=csc²x)
  
 equation 'a' represent the equation of hyperbola which is (x²/a²)-(y²/b²) =1 with given conditions( a=1,b=1)

So, option D is correct