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Usimov [2.4K]
3 years ago
15

The point-slope form of the equation of the line that passes through points (-5,-1) and (10, -7 ) is y-4=1/4 (x-8) what is the s

lope intercept form of the equation for this line​ ?
Mathematics
1 answer:
arlik [135]3 years ago
4 0

Answer:

y = \frac{1}{4} x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

y - 4 = \frac{1}{4} (x - 8) ← distribute

y - 4 = \frac{1}4} x - 2 ( add 4 to both sides )

y = \frac{1}{4} x + 2 ← in slope- intercept form

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What is 0.5×(-0.6) ×0.4= and pls show how​
blondinia [14]

Answer:

- 0.12

Step-by-step explanation:

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3 years ago
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5 0
3 years ago
Point M is on line segment LN. Given LN = 9, MN = 4x, and LM=5x
andrew-mc [135]

Answer:

MN = 4

Step-by-step explanation:

Given that L, M, N are collinear,

LN = 9,

MN = 4x

LM = 5x

Required:

Length of MN

SOLUTION:

To calculate the numerical length of MN, we need to find the value of x.

To find the value of x, generate an equation to solve for x as follows:

LM + MN = LN (segment addition postulate)

5x + 4x = 9 (substitution)

Solve for x

9x = 9

Divide both sides by 9

\frac{9x}{9} = \frac{9}{9}

x = 1

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plug in the value of x

MN = 4(1) = 4

5 0
3 years ago
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