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Cerrena [4.2K]
3 years ago
7

PLLLLEEEEEAAASEEE HELP ME!!!

Mathematics
1 answer:
Oxana [17]3 years ago
5 0

The total of a triangle must be 180 degrees, so since c = z, then z is 35 degrees, add that to the 65 degrees of angle x to get 100, so the angle must be an 80 degrees, so angle y is 80 degrees
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Josh estimates the height of his desk. what is the reasonable estimate?…
Ugo [173]
I cant answer if there is no info
5 0
3 years ago
¿Cuál es el volumen en pulgadas cúbicas de una esfera cuya circunferencia mide 64 pulgadas?
pochemuha

Answer:

4445.18 pulgadas cúbicas

Step-by-step explanation:

Paso 1

La fórmula para la circunferencia de una esfera = 2πr

Circunferencia de una esfera = 64 pulgadas

Por eso,

64 = 2πr

Por lo tanto, encontramos r

Dividir ambos lados por 2π

64 / 2π = 2πr / 2π

r = 10.185916358 pulgadas

Radio r = 10.2 pulgadas

Paso 2

Volumen de una esfera

= 4/3 × π × r³

r = 10.2 pulgadas

Por lo tanto, 4/3 × π × (10.2) ³

= 4445.18 pulgadas cúbicas

Por lo tanto, el volumen en pulgadas cúbicas de una esfera = 4445.18 pulgadas cúbicas

6 0
3 years ago
What is the product?
Sonja [21]
3/22 is the answer in simplest form
6 0
3 years ago
Read 2 more answers
Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
nirvana33 [79]

Answer:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}

And solving for \frac{dh}{dt} we got:

\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}

We need to convert the rate given into m^3/min and we got:

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

5 0
4 years ago
Solve 2x^4/7 x 3/2x
Paha777 [63]
The answer is =3x^6/7
6 0
3 years ago
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