What is the volume of a regular pyramid having a base area of 24 inches and height of 6 inches
2 answers:
<h3>❁ Question -:</h3>
If the base area of a regular pyramid is 24 inches and the height is 6 inches. Find the volume of the regular pyramid ?
<h3>❁ Explanation -:</h3>
In this question we are provided with the base area that is 24 inches and it is also given that the height is 6 inches. We are asked to calculate the volume of the regular pyramid.
We know,
Where,
B stand for base area. H stand for height. Substituting the values we get
Hence the volume of the pyramid is 48 inches ³. <em>NoTe </em> <em>:</em> <em> </em> <em>Always make sure </em><em>that </em><em>the </em><em>volume </em><em>will </em><em>be </em><em>in </em><em>units³</em><em>.</em>
Answer:
V= 48 in^2
Step-by-step explanation:
Formula
Since the base has a known area, we do not need the full volume formula. This formula is
<em>V = B * h / 3</em>
B is the area of the base and h is the height measured from the top of the pyramid to the base meeting the base at right angles.
Givens
B = 24 in^2
h = 6 in
Solution
V = B * h / 3
V = 24 * 6/3
V= 48 in^2
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The answer to 2y+7(y-3)=60 is y=9
Answer:
Step-by-step explanation:
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First of all we have to find the slope m = y₂-y₁ / x₂-x₁ m = -8 + 16 / -10 + 8 m = 8/-2 m = -4 y-y₁ = m (x-x₁) y + 8 = -4 (x + 10) y + 8 = -4x - 40 y = -4x -40 - 8 y = -4x -48
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Step-by-step explanation:
What you do is you multiply 1.25 by 7.
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