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kondor19780726 [428]
1 year ago
13

What is the volume of a regular pyramid having a base area of 24 inches and height of 6 inches

Mathematics
2 answers:
Nimfa-mama [501]1 year ago
8 0
<h3>❁ Question -:</h3>

If the base area of a regular pyramid is 24 inches and the height is 6 inches. Find the volume of the regular pyramid ?

<h3>❁ Explanation -:</h3>

In this question we are provided with the base area that is 24 inches and it is also given that the height is 6 inches. We are asked to calculate the volume of the regular pyramid.

We know,

✡ \:  \small \underline{ \boxed{\sf {{Volume_{(pyramid)} = \dfrac{1}{3}×B × H}}}}

Where,

  • B stand for base area.
  • H stand for height.

Substituting the values we get

\small\frak{ Volume_{(pyramid)} = \dfrac{1}{3}×24 × 6}

\small\frak{ Volume_{(pyramid)} = 24 × 2}

\small\frak {Volume_{(pyramid)} =48 \: inches}

\small \underline{\boxed{ \frak{ Volume \:  of  \: a  \: pyramid = 48 {inches }^{3} }}}

  • Hence the volume of the pyramid is 48 inches ³.

<em>NoTe </em><em>:</em><em> </em><em>Always make sure </em><em>that </em><em>the </em><em>volume </em><em>will </em><em>be </em><em>in </em><em>units³</em><em>.</em>

Anestetic [448]1 year ago
6 0

Answer:

V= 48 in^2

Step-by-step explanation:

Formula

Since the base has a known area, we do not need the full volume formula. This formula is

<em>V = B * h / 3</em>

B is the area of the base and h is the height measured from the top of the pyramid to the base meeting the base at right angles.

Givens

B = 24 in^2

h = 6 in

Solution

V = B * h / 3

V = 24 * 6/3

V= 48 in^2

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Answer:

Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proof is below.

Step-by-step explanation:

Given:

In Δ PQT

PQ = 30 ft

QT = 28 ft

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In Δ QRS

QR = 15 ft

RS = 14 ft

SQ = 10 ft

To Prove:

Δ PQT ~ Δ QRS

Proof:

First we consider  the ratio of the sides

\frac{PQ}{QR}=\frac{30}{15} = \frac{2}{1}            ..............( 1 )

\frac{QT}{RS}=\frac{28}{14} = \frac{2}{1}            ..............( 2 )

\frac{TP}{SQ}=\frac{20}{10} = \frac{2}{1}            ..............( 3 )

So By equation ( 1 ), ( 2 ) and  ( 3 ) we get

\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}

Now in Δ PQT  and Δ QRS we have

\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}

Which are corresponding sides of a similar triangle in proportion.

∴ Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proved

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Step-by-step explanation:

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You multiple 10 by 0.08 =0.8
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Step-by-step explanation:

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