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sleet_krkn [62]
2 years ago
12

HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH

Mathematics
1 answer:
8090 [49]2 years ago
8 0

Hello, please consider the following.

We will multiply the numerator and denominator by

4+\sqrt{6x}

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

Thank you

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bagirrra123 [75]
1) 300miles X $0.20 = $60

2) $50 + $60 = $110

They spent $110 for the car.
6 0
3 years ago
What is X in the equation -15x+15(-4)=-30
love history [14]

<em><u>Answer: x=-2 *The answer should be the negative sign.*</u></em>

Step-by-step explanation:

distributive property: a(b+c)=ab+ac

remove parenthesis

-15x-15*4=-30

15*4=60

-15x-60=-30

add 60 both sides of an equation.

-15x-60+60=-30+60

simplify.

-15x=30

divide by -15 both sides of an equation.

-15x/-15=30/-15

simplify.

30/15=2

x=-2

Hope this helps!

Thanks!

Have a great day!

7 0
3 years ago
Which ratio is equivalent to 1:1
Lynna [10]

Answer:

the answer is 1

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6 0
3 years ago
What is the distance between (-5, 5) and (1, -2)
Murrr4er [49]

Answer:

\displaystyle d=\sqrt{85}\text{, or about 9.22 units}

Step-by-step explanation:

          We will use the distance formula to solve.

\displaystyle d=\sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1})^2}

\displaystyle d=\sqrt{(1--5)^2 +(-2-5)^2}

\displaystyle d=\sqrt{(6)^2 +(-7)^2}

\displaystyle d=\sqrt{36+49}

\displaystyle d=\sqrt{85}\text{, or about 9.22 units}

<em>Read more about using the </em><em>distance formula</em><em> here: brainly.com/question/15691280</em>

6 0
1 year ago
Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,
Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁,  of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}

Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times  (720-576)\times  (720 - 672)}

Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times  144 \times  48} = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}

The semi-perimeter, s₂,  of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times  (690 -228)\times  (690 - 480)}

Area\, of \, \Delta ACD = \sqrt{690 \times 18\times  462\times  210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

4 0
3 years ago
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