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2 years ago

9

HELP ANSWER ASAP PLS Given the following diagram, find the trigonometric ratios.

1 answer:

saveliy_v [14]2 years ago

5 0

Answer:

sin B = 15/17

Cos B = 8/17

Tan B = 15/8

Step-by-step explanation:

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Scarlett is trying to find the height of a dam. She stands 90 meters away from the dam and records the angle of elevation to the

adoni [48]

Answer:

45.55 meters

Step-by-step explanation:

I'm guessing she recorded above her height, right?

To find the height of the dam, use the tangent ratio:

$tangentX=\frac{opposite}{adjacent}$

The height of the dam is the side opposite the given angle, and this will represent x. The adjacent side (the hypotenuse is NEVER considered the adjacent side) is the distance from Scarlett to the dam. The angle of elevation is the angle of 26°. Insert the values:

$tan26=\frac{x}{90}$

Solve for x. Multiply both sides by 90:

$90*(tan26)=90*(\frac{x}{90})\\\\90*tan26=x$

Insert equation into a calculator:

$x=90*tan26\\\\x=43.9$

Now add Scarlett's height:

$43.9+1.65=45.55$

The dam is 45.55 meters tall.

<em>Finito</em> :D

6 0

3 years ago

4. An equilateral triangle has a perimeter of 60 cm. Find the exact<br> altitude of the triangle.

taurus [48]

Step-by-step explanation:

<h2>GIVEN:-</h2>

The Perimeter of Equilateral triangle = 60cm

<h2>UNDERSTANDING THE CONCEPT:-</h2>

According to the question,

To find the height of the triangle,

Perimeter of Equilateral triangle = Area of Equilateral triangle.

<h2>FORMULA USED:-</h2>

$60 = \frac{ \sqrt{3} }{4} a {}^{2} \\$

<h2>REQUIRED ANSWER:-</h2>

$60 \times 4 = \sqrt{3a {}^{2} }$

$a {}^{2} = 240 \sqrt{3} \\$

$a = 120 \sqrt{3} cm$

<h3>SO, The Exact height of the triangle is 120√3cm.</h3>

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2 years ago

What would be the answer to this question?

sergejj [24]

Answer: the answer would be 66

Step-by-step explanation:

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3 years ago

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As quick as possible please <br><br> What is another name for <1?

Reika [66]

Greater then or less then

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2 years ago

Help ASAP!!!<br> Worth 30 points!!!

sladkih [1.3K]

$2m+22$

I hope this helped!

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3 years ago

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