Answer:
60 minutes for the larger hose to fill the swimming pool by itself
Step-by-step explanation:
It is given that,
Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.
takes 30 minutes for the larger hose to fill the swimming pool by itself
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
<u>To find LCM of 20 and 30</u>
LCM (20, 30) = 60
<u>To find the efficiency </u>
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
x = 60/30 =2
x + y = 60 /20 = 3
Therefore efficiency of y = (x + y) - x =3 - 2 = 1
so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes
1. The withdrawals adds up to 291+99+150+12= 552
500-552= -52
2. The bus pass which cost $150.
3.1000-552= $448 left
4.1000-552-300-150=$-2 left. Withdrawal had happened.
7/3 you divide 3.5 by 1.5 and get 2.3333333 which in fraction form is 7/3
Answer:

Step-by-step explanation:
Using central Limit Theorem (CLT), The sum of 100 random variables;
is approximately normally distributed with
Y ~ N (100 ×
) = N ( 50,
)
The approximate probability that it will take this child over 55 seconds to complete spinning can be determined as follows;
N ( 50,
)




Using Chebyshev's inequality:

Let assume that X has a symmetric distribution:
Then:


where: (
)

Answer:
1/4 cup of sugar to 1 cup of water
Step-by-step explanation:
you divide 2 by 8 and get 0.25 and that is 1/4.
Hope this helps!!