Question:
Which system has the same solution as the teacher's system?
Systems of equations that have the same solution are called equivalent systems.We are given with a system of two equations, we can make an equivalent system by substituting one equation by the sum of the two equations.
Given System:
<span>
8x-16y=14</span>→eq.1
−x+5y=−3→eq.2<span>
Teacher's Solution:
From eq.2
x = 5y + 3
Substituting the value of x in eq.1
We get,
</span> 8(5y + 3) - 16y = 14
40y + 24 - 16y = 14
24y + 24 = 14
24y = 14-24
24y = -10
y = -10/24
y = -5/12
Substituting y-value in eq.2,
−x+5(-5/12) = −3
-x -25/12 = -3
-x = -3 + 21/12
-x = 15/12
x = -5/4
<span>Fabiano:
</span> 3x−15y=<span>9
</span> 8x−16y=−<span>7
</span>Rearranging both equations:
y = 1/5x - 3/5
y = 1/2x+7/16
Placing both equations equal to each other,
1/5x - 3/5= 1/2x+7/16
1/5x -1/2x = 7/16 +3/5
-3/5x = 83/80
x = -83×5/80×3
x = -415/240
x = -83/48
This doesnt matches the teachers solution so we will move to sonali.
<span>Sonali
</span> −x+5y=−<span>3
</span> −4x+8y=−7
Rearranging both equations:
y = 1/5x - 3/5
y = 1/2x -7/8
Placing both equations equal to each other,
1/5x - 3/5 = 1/2x -7/8
1/5x -1/2x = -7/8 +3/5
-3/10x = -11/40
x = 110/120
x = 11/12
This doesn't match the teacher's solution either, so we will conclude that none of the solutions to the system of equation has the same answer as the teacher.
You should times each side by 3/2, so your answer is C.
the answer that I came up with is (c)
Answer:
-
Step-by-step explanation:
Given:
10 poker chips:
Let the stack has positions (1,2,3,4,5,6,7,8,9,10)
So we can find all possible outcomes of the stack is:
=
and the possibility of a stack to be identical while flipping is:
So the different 10-chip stacks can Dave make if two stacks are not considered distinct:
-