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Reptile [31]
3 years ago
13

Will somebody answer this problem please

Mathematics
1 answer:
pochemuha3 years ago
6 0
Apply the standard equation of a circle with center at (h,k) and radius r:

(x-h)^2 + (y-k)^2 = r^2

Using the given data,

(x-2)^2 + (y+4)^2 = 3^2
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Write the linear equation in slope-intercept from the information given.
alexandr1967 [171]

Answer:

B)  y = -3x+2

Step-by-step explanation:

plug (2,-4) and -3 into y = mx + b to find 'b'

-4 = -3(2) + b

b = -4+6 = 2

4 0
2 years ago
4) FRIDAY: An unknown quantity which is represented by a letter or a symbol is called _____
lukranit [14]

Answer:

A Variable

Step-by-step explanation:

Variables are used to mark an unknown value. Common math problems ask you to solve for it.

For example in 5x+23=45, 'x' is the variable.

A constant is a number without a variable.

<em>Brainilest Appreciated. </em>

8 0
2 years ago
Which set of three numbers could be the side lengths of a triangle?
Tresset [83]

Answer:

<h2>А. 3, 5, 7</h2><h2 />

Step-by-step explanation:

Because

7 - 3 = 4

7 + 3 = 10

then

7 - 3 < 5 < 7 + 3

the 3 other cases don’t fit with this rule.

5 0
3 years ago
Solve the inequality graph and check the solution.<br> 5&gt;z-3
AnnZ [28]

Answer:

z < 8

Step-by-step explanation:

Add 3 to both sides

8 > z OR z < 8

7 0
3 years ago
How do I subtract decimals from whole numbers?
Gekata [30.6K]

Answer:

Just use long subtraction by expanding the decimal places of the whole number. This is done by adding a point, and enough zeros to it to match the number of decimal digits in the other number (digits after the decimal point).

12345678

i.e: 5 - 2.48374827, 2.48374827 has 8 decimal digits, so add 8 zeros after the point.

=

1 1 1 1 1 1 1

5.00000000

-

2.48374827

_______________

2.51625173

7 + 3 = <u>1</u>0, 7 + 2 + <u>1</u> = <u>1</u>0, 8 + 1 + <u>1</u>= <u>1</u>0, 5 + 4 + <u>1</u> = <u>1</u>0, 2 + 7 + <u>1</u> = <u>1</u>0, 3 + 6 + <u>1</u> = <u>1</u>0, 1 + 8 + <u>1</u> = <u>1</u>0, 5 + 4 + <u>1</u> = <u>1</u>0, 2 + 2 + <u>1</u> = <u>5</u><u> </u><u>:</u><u> </u>5.00000000

This is basically borrowing a group of 10s which are the same as 1s in the next decimal place up.

For each digit except the first to the right, let 10 subtract that number from it and minus 1 since the 1 is carried over.

7 0
3 years ago
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