Evaluate the surface integral. s xyz ds, s is the cone with parametric equations x = u cos(v), y = u sin(v), z = u, 0 ≤ u ≤ 3, 0 ≤ v ≤ π 2
2 answers:
Answer:
Step-by-step explanation:
Let
Differentiate partially with respect to u, v.
To find f, put in xyz.
So,
Integrate with respect to u.
Integrate with respect to v.
Let's capture the parameterization of the surface
by the vector function
Then the surface element is given by
So the surface integral is equivalent to
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