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3 years ago

Why aren't flowers sold at a monastery math worksheet answers?

Chemistry

2 answers:

maria [59]3 years ago

8 0

1) x/9 + 16 = 5.

a) x/9 + 16 - 16 = 5 -16; subtraction.

b) x/9 = -11; simplifying.

c) x/9 · 9 = -11 · 9; multiplication.

d) x = -99; simplifying.

2) 5 · (2a - 3) = 60.

a) 10a - 15 = 60; distributive.

b) 10 - 15 + 15 = 60 + 15; addition.

c) 10a = 75; simplifying.

d) 10a ÷ 10 = 75 ÷ 10; commutative.

e) a = 7.5; simplifying.

3) 4 n + (7 + n) = 52.

a) 4n + (n + 7) = 52; commutative.

b) ( 4n + n) + 7 = 52; associative.

c) 5n + 7 = 52; combining.

d) 5n + 7 - 7 = 52 - 7; subtraction.

e) 5n = 45; simplifying.

f) 5n ÷ 5 = 45 ÷ 5; division.

g) n = 9; simplifying.

4) 8t - 3 · (4t + 2) = 16.

a) 8t - 12 t - 6 = 16; distributive.

b) -4 t - 6 = 16; combining.

c) - 4 t - 6 + 6 = 16 + 6; addition.

d) -4t = 22; simplifying.

e) -4t ÷ (-4) = 22 ÷ (-4); division.

f) t = -5.5; simplifying.

This is the question I found on internet.

nordsb [41]3 years ago

3 0

<span>Flowers are not sold at a monastery math in order to precevent florist Friahs. Friars were behind on their belfry payments and they opened up a small florist shop to raise funds. Through this Friar Florist, everyone like to buy flowers from the men of God then a rival florist across town thought that this was unfair. </span>

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Explanation:

I've numbered the isomeric hexanes from 1 to 5 and labelled the sets of equivalent hydrogens.

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If a 1.00 mL sample of the reaction mixture for the equilibrium constant experiment required 32.40 mL of 0.258 M NaOH to titrate

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Answer:

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Explanation:

Step 1: Data given

Volume of acetic acid = 1.00 mL = 0.001 L

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Step 3: Calculate the concentration of the acetic acid

b*Ca*Va = a*Cb*Vb

⇒with b = the coefficient of NaOH = 1

⇒with Ca = the concentration of CH3COOH = TO BE DETERMINED

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⇒with a = the coefficient of CH3COOH = 1

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Ca * 0.001 L = 0.258 * 0.03240

Ca = 8.36 M

The concentration of acetic acid is 8.36 M

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